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Vaselesa [24]
3 years ago
5

2. Emily hopes to be at least 72 inches tall. Right now she is 56 inches tall. Write

Mathematics
1 answer:
katovenus [111]3 years ago
4 0

Answer:

x ≥ 16

He'll like to grow atleast 16 inches more

Step-by-step explanation:

Given :

Present height, p = 56 inches

Final height, f is atleast 72 inches ; f ≥ 72

Let additional height required = x

Writing the problem as an inequality ;

Present + additional height ≥ final height

56 + x ≥ 72

x ≥ 72 - 56

x ≥ 16

He'll like to grow atleast 16 inches more

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9

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3 years ago
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8

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WHAT IS 4 TIMES TWO THIRDS IN A MIXED FRACTION
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\frac{4}{1}×\frac{2}{3}=\frac{8}{3}
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3 years ago
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Square ABCD was translated using the rule (x, y) → (x – 4, y + 15) to form A'B'C'D'. What are the coordinates of point D in the
Vitek1552 [10]

Answer:

D = (13, - 23 )

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Given the translation rule

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3 0
3 years ago
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RSB [31]

Answer:

Step-by-step explanation:

3x² - 3x + 7 = 0

a = 3 ; b = -3 and c = 7

D = b² - 4ac = (-3)² - 4*3*7

D = 9 - 84 = - 75

D = 75i²

√D = √75i² = \sqrt{5*5*3 * i * i}= 5i\sqrt{3}

x = \dfrac{-b+\sqrt{D}}{2a}  \ ; \  x=\dfrac{-b-\sqrt{D}}{2a}\\\\ \\x=\dfrac{3+5i\sqrt{3}}{6} ; \ ; x = \dfrac{3-5i\sqrt{3}}{6}\\\\\\x =\dfrac{3}{6}+\dfrac{5i\sqrt{3}}{6} ; \ ; x=\dfrac{3}{6}-\dfrac{5i\sqrt{3}}{6}\\\\\\Solution:\\\\x=\dfrac{1}{2}+\dfrac{5\sqrt{3}}{6}i ; \ ; x=\dfrac{1}{2}-\dfrac{5\sqrt{3}}{6}i

5 0
2 years ago
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