Answer:
For t=3 sec the velocity change from positive to negative
Step-by-step explanation:
we have

This is the equation of a vertical parabola open downward (the leading coefficient is negative)
where
s(t) is the distance in feet
t is the time in seconds
We know that
To find out when the velocity change from positive to negative, we need to determine the turning point of the quadratic equation
The turning point of the quadratic equation is the vertex
so
Convert the quadratic equation into vertex form

Factor -16

Complete the square


Rewrite as perfect squares

The vertex is the point (3,244)
therefore
For t=3 sec the velocity change from positive to negative
Answer:
Expression is; 29 - x = 16
I've attached an image showing the number line
Step-by-step explanation:
We are told that at lunchtime, it was 29 degrees Celsius and that by sunset, the temperature had dropped to 16 degrees Celsius.
Let the drop be x.
Thus;
29 - x = 16
I've attached an image showing the number line
Lol i was working on this earlier. First get rid of the parenthesis by distributing the powers to the other powers.
27/4x(6)y(8)
the () are for powers
Answer:
22 x^2
Step-by-step explanation:
Simplify the following:
11 x^2 + 11 x^2
Hint: | Add like terms in 11 x^2 + 11 x^2.
11 x^2 + 11 x^2 = 22 x^2:
Answer: 22 x^2
none of your answers are correct.
Your answer will be choice A.
a = 15.1, b = 23.5, perimeter = 56.6