Answer: The answer is 105 ft. and 35 ft.
Step-by-step explanation: Given that Mauro has 140 ft. of rope, which he wants to cut into two pieces such that the length of the longer piece is 3 times the length of the shorter piece. We need to find the lengths of both the pieces.
Let 'x' and 'y' be the lengths of the longer piece and shorter piece respectively. Then, we will have the following system of equations.

Substituting the value of 'x' from the second equation in the first equation, we have

Thus, length of longer piece = 3 × 35 = 105 ft., and length of shorter piece = 35 ft.
Answer:
20 or 18
Step-by-step explanation:
Answer:
Circular paraboloid
Step-by-step explanation:
Given ,

Here, these are the respective
axes components.
- <em>Component along x axis
</em>
- <em>Component along y axis
</em>
- <em>Component along z axis
</em>
We see that , from the parameterised equation , 
This can also be written as :

This is similar to an equation of a parabola in 1 Dimension.
By fixing the value of z=0,
<u><em>We get
which is equation of a parabola curving towards the positive infinity of y-axis and in the x-y plane.</em></u>
By fixing the value of x=0,
<u><em>We get
which is equation of a parabola curving towards positive infinity of y-axis and in the y-z plane. </em></u>
Thus by fixing the values of x and z alternatively , we get a <u>CIRCULAR PARABOLOID. </u>
Answer:
The probability that at least 280 of these students are smokers is 0.9664.
Step-by-step explanation:
Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers
The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.
But the sample selected is too large and the probability of success is close to 0.50.
So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:
1. np ≥ 10
2. n(1 - p) ≥ 10
Check the conditions as follows:

Thus, a Normal approximation to binomial can be applied.
So,

Compute the probability that at least 280 of these students are smokers as follows:
Apply continuity correction:
P (X ≥ 280) = P (X > 280 + 0.50)
= P (X > 280.50)

*Use a <em>z</em>-table for the probability.
Thus, the probability that at least 280 of these students are smokers is 0.9664.