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stepladder [879]

3 years ago

11

Of the cakes at Naomi's Bakery, 1/6 have chocolate frosting. Of the cakes with chocolate frosting, 1/5 have raspberry filling. W

hat fraction of the cakes at Naomi's Bakery have both chocolate frosting and raspberry filling?

1 answer:

Sever21 [200]3 years ago

5 0

Answer:

$\frac{1}{6} \times \frac{1}{5 } \\ \frac{1}{30}$

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Given that there are 60 minutes in an hour and Mr. Sneed runs his new machine eight hours per day how many bottles does this mac

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Step-by-step explanation:

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2 years ago

Graph the linear function w(x)=3/5x+2<br> All I need is the ordered pairs/points

Anastaziya [24]

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Answer:

(0, 2), (5, 5)

Step-by-step explanation:

The w-intercept is the constant in the equation, so you know immediately that (x, w) = (0, 2) is one point on your graph.

Since the value of x is being multiplied by 3/5, it is convenient to choose an x-value that is a multiple of 5. When x=5, we have ...

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3 0

3 years ago

Solve A = p(1+rt) for t

Svetlanka [38]

A = p(1 + rt)
A/p = 1 + rt
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7 0

3 years ago

A coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that

mafiozo [28]

Answer:

(a) The significance level of the test is 0.002.

(b) The power of the test is 0.3487.

Step-by-step explanation:

We are given that a coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that the probability is not 0.5.

The test rejects the null hypothesis if either 0 or 10 heads are observed.

Let p = <u><em>probability of obtaining head.</em></u>

So, Null Hypothesis, $H_0$ : p = 0.5

Alternate Hypothesis, $H_A$ : p $\neq$ 0.5

(a) The significance level of the test which is represented by $\alpha$ is the probability of Type I error.

Type I error states the probability of rejecting the null hypothesis given the fact that the null hypothesis is true.

Here, the probability of rejecting the null hypothesis means we obtain the probability of observing either 0 or 10 heads, that is;

P(Type I error) = $\alpha$

P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true) = $\alpha$

Also, the event of obtaining heads when a coin is thrown 10 times can be considered as a binomial experiment.

So, X ~ Binom(n = 10, p = 0.5)

P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true) = $\alpha$

$\binom{10}{0}\times 0.5^{0} \times (1-0.5)^{10-0} +\binom{10}{10}\times 0.5^{10} \times (1-0.5)^{10-10}$ = $\alpha$

$(1\times 1\times 0.5^{10}) +(1 \times 0.5^{10} \times 0.5^{0})$ = $\alpha$

$\alpha$ = 0.0019

So, the significance level of the test is 0.002.

(b) It is stated that the probability of heads is 0.1, and we have to find the power of the test.

Here the Type II error is used which states the probability of accepting the null hypothesis given the fact that the null hypothesis is false.

Also, the power of the test is represented by (1 - $\beta$ ).

So, here, X ~ Binom(n = 10, p = 0.1)

$1-\beta$ = P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true)

$1-\beta$ = $\binom{10}{0}\times 0.1^{0} \times (1-0.1)^{10-0} +\binom{10}{10}\times 0.1^{10} \times (1-0.1)^{10-10}$

$1-\beta$ = $(1\times 1\times 0.9^{10}) +(1 \times 0.1^{10} \times 0.9^{0})$

$1-\beta$ = 0.3487

Hence, the power of the test is 0.3487.

3 0

3 years ago

What is the solution to the proportion 3y-8/12=y/5? can someone help me do this?

RideAnS [48]

$\displaystyle\\
 \frac{3y-8}{12} = \frac{y}{5} \\ \\ 
5(3y-8)=12y\\\\
15y-40=12y\\\\
3y = 40\\\\
\boxed{y = \frac{40}{3}}$

3 0

3 years ago

Read 2 more answers