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NISA [10]
3 years ago
5

Pls help I really need a good grade on this

Mathematics
1 answer:
Aneli [31]3 years ago
8 0

Answer:

(30+10n)+(95+7n)= t

Step-by-step explanation:

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Find the first four terms of the arithmetic sequence<br> where a1 = 2 and d = 5 (use formula)
FinnZ [79.3K]

Answer:

first four terms are 2, 7, 12, 17

Step-by-step explanation:

use this formula:  a_{n} = a_{1} + (n - 1)· d

where 'n' equals the position in the sequence the term is in and 'd' is the common difference

if a_{1} = 2 and d = 5 are given, plug those into formula

a_{1} = 2

a_{2} = 2 + (2 - 1)·5 = 2+5 = 7

a_{3} = 2 + (3 - 1)·5 = 2+2(5) = 12

a_{4} = 2+(4 - 1)·5 = 2+3(5) = 17

8 0
3 years ago
what is the constant of proportionality (in miles per hour) based on the table? (can you please help me)
Nookie1986 [14]

Answer:

45 ( please label me brainliest)

Step-by-step explanation:

6 0
3 years ago
A rectangular field is 75 yards wide and 105 yards long
nika2105 [10]

Answer:

width = 72 yards

length = 108 yards

Step-by-step explanation:

Given:

  • Width = 75 yards
  • Length = 105 yards

<u>Area of the field</u> with the given values:

\begin{aligned}\textsf{Area of a rectangle}&=\sf width \times length\\& = \sf 75 \times 105\\& = \sf 7875\:\: yd^2\end{aligned}

To maintain the <u>same perimeter</u>, but <u>change the area</u>, either:

  • decrease the width and increase the length by the same amount, or
  • increase the width and decrease the length by the same amount.

In geometry, length pertains to the <u>longest side</u> of the rectangle while width is the <u>shorter side</u>.  Therefore, we should choose:

  • decrease the <u>width</u> and increase the <u>length</u> by the <u>same amount</u>.

<u>Define the variables</u>:

  • Let x = the amount by which to decrease/increase the width and length.

Therefore:

\implies \sf width \times length < 7875\:\:yd^2

\implies (75-x)(105+x) < 7875

Solve the inequality:

\begin{aligned}(75-x)(105+x) & < 7875\\7875-30x-x^2 & < 7875\\-x^2-30x & < 0\\-x(x+30) & < 0\\x(x+30) & > 0\\\implies x & > 0 \:\: \textsf{ or }\:\:x < - 30\end{aligned}

Therefore, as distance is positive only and the maximum width is 75 yd (since we are subtracting from the original width):

\begin{cases}\textsf{width} = 75 - x\\\textsf{length} = 105 + x\end{cases}

\textsf{where } 0 < x < 75

Therefore, to find the width and length of another rectangular field that has the same perimeter but a smaller area than the first field, simply substitute a value of x from the restricted interval into the found expressions for width and length:

<u>Example 1</u>:

  • Let x = 3

⇒ Width = 75 - 3 = 72 yd

⇒ Length = 105 + 3 = 108 yd

⇒ Perimeter = 2(72 + 108) = 360 yd

⇒ Area = 72 × 108 = 7776 yd²

<u>Example 2</u>:

  • Let x = 74

⇒ Width = 75 - 74 = 1 yd

⇒ Length = 105 + 74 = 179 yd

⇒ Perimeter = 2(1 + 179) = 360 yd

⇒ Area = 1 × 179 = 179 yd²

4 0
2 years ago
Read 2 more answers
Mr. Yu applies 12 ounce of fertilizer to every 58 square meter of his lawn.How many ounces of fertilizer does Mr. Yu use per squ
DedPeter [7]
1/2 divided by 5/8 
Keep  Change  Flip=

1/2 x 8/5= 0.8 
0.8 = 8/10 simpified 4/5 

Answer: 4/5 
7 0
3 years ago
Help help help help help
attashe74 [19]

Answer:

i dont now

Step-by-step explanation:

inde man kona ka balo sorry

7 0
3 years ago
Read 2 more answers
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