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Setler [38]
2 years ago
11

Help help help help help

Mathematics
2 answers:
attashe74 [19]2 years ago
7 0

Answer:

i dont now

Step-by-step explanation:

inde man kona ka balo sorry

Dafna1 [17]2 years ago
3 0

Answer:

quadrant 1 and quadrant IV

Step-by-step explanation:

(a)

secθ > 0 in quadrants 1 and IV

sinθ > 0 in quadrants 1 and II

Thus θ is in quadrant I

(b)

cosθ > 0 in quadrants I and IV

cotθ < 0 in quadrants II and IV

Thus θ is in quadrant IV

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Find the parabola with equation y = ax2 + bx whose tangent line at (3, 12) has equation y = 10x − 18. y = incorrect: your answer
pishuonlain [190]
For these questions to be true and the equation of the tangent to have an equal y to the equation of the parabola i guess there has to be a "c" and in that case integrate the equation of the tangent you will have a = 5 and b = -18 then you substitute in the equation of the parabola with the point you have you will find that "c" = 21 and so the equation of the parabola becomes y = 5x^2 - 18 x +21
 
3 0
2 years ago
What inequality describes the solutions of 2y less than or equal to 8?
Tanzania [10]

Answer:

y\leq 4

Step-by-step explanation:

Start with the given

2y\leq 8\\

Divide the two on both sides to get

y\leq 4

8 0
3 years ago
Read 2 more answers
Какая фигура имеет ось симметрии и центр симетрий​
Zigmanuir [339]

Answer:

Проведите линию через форму, чтобы каждая сторона была зеркальным отражением. Когда фигура складывается пополам по оси симметрии, две половинки совпадают. На этой фотографии белая линия по центру представляет собой вертикальную ось симметрии.

Step-by-step explanation:

5 0
3 years ago
TIMED QUESTION NEED HELP FASTWhat values of b satisfy 3(2b + 3)2 = 36?
egoroff_w [7]

Answer:

\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}

Step-by-step explanation:

3(2b+3)^{2}=36\\\frac{3(2b+3)^{2}}{3}=\frac{36}{3}\\(2b+3)^{2}=12

Taking square root both sides, we get

\sqrt{(2b+3)^{2}}=\pm \sqrt{12}\\2b+3=\pm \sqrt{4\times 3}\\2b+3=\pm 2\sqrt{3}\\2b+3-3=\pm 2\sqrt{3}-3\\2b=-3\pm 2\sqrt{3}\\b=\frac{-3\pm 2\sqrt{3}}{2}\\b=\frac{-3+ 2\sqrt{3}}{2}\textrm{ or }b=\frac{-3- 2\sqrt{3}}{2}

Therefore, the values of b are:

\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}

5 0
3 years ago
Read 2 more answers
I have a strange True or False question on my packet.. But here I go: "A trapezoid has two 90 degree angles." Is it true or fals
alex41 [277]

Answer:

False unless a right trapezoid.

Step-by-step explanation:

All trapezoids have 4 angles which add to 360 degrees. The angles can be any measure except in a right trapezoid which does have two 90 degree angles. It is not a requirement to be a trapezoid though so this is false.

8 0
3 years ago
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