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Answer:
x = sqroot(122)
Step-by-step explanation:
First find the line that goes thru the middle of the shape. It is the hypotenuse of the bottom/left triangle. Use the pythagorean thm.
9^2 + 5^2 = h^2
81 + 25 = h^2
sqroot106 = h
Now sqroot106 is a leg in the right triangle that is on the top/right in the image.
Use pythagorean thm again.
4^2 + (sqroot106)^2
= x^2
16 + 106 = x^2
122 = x^2
sqroot122 = x
