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erma4kov [3.2K]
3 years ago
7

Tony has $20. He wants to buy at least 4

Mathematics
1 answer:
zavuch27 [327]3 years ago
6 0

Tony has $20. He wants to buy at least 4

snacks. Hot dogs (x) are $3 each.

Peanuts (y) are $2 each.​

Answer:

To solve the above question, we use the below inequality equations

x + y ≥ 4 snacks .........Inequality equation 1

3x + 2y ≤ $20 ..........Inequality equation 2

Step-by-step explanation:

We can make use of the inequality equations

Hot dogs = (x) are $3 each.

Peanuts = (y) are $2 each.​

He wants to buy at least 4

x + y ≥ 4 snacks .........Inequality equation 1

3x + 2y ≤ $20 ..........Inequality equation 2

From the above inequality equations, Tony can buy at least 4 snacks but he can only spend $20.

Let take a random number, where x = 4, and y = 4. This means Tony can buy

a) 4($3) + 4($2) = 12 + 8 = $20

The total number of snacks = 4 + 4 = 8 snacks.

b)

This answer above confirms the inequality equations 1 and 2

x + y ≥ 4 snacks .........Inequality equation 1

8 snacks ≥ 4 snacks

3x + 2y ≤ $20 ..........Inequality equation 2

$20 ≤ $20

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<em>here's</em><em> your</em><em> solution</em>

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8 0
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8-6y=11
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So for my opinion the solution is A.(3,-1/2)
4 0
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