Ok, so
Quadrants are found on coordinate planes. So the first number tells you to go on the X axis. It goes this way ---------
you look on the left side side of the origin (zero) and go to -5
since the second umber will be found on the Y axis, and is positive, go up to 4.
That is how you find your point. The qudrants are counted like this.
2 1
3 4
The answer is Quadrant 2
Hope it helped☺
Answer:
x = 4
Step-by-step explanation:
When a tangent and a secant are drawn from an external point to a circle.
Then the product of the external part of the secant and the entire secant and the square of the measure of the tangent are equal, hence
x(x + 5) = 6²
x² + 5x = 36 ( subtract 36 from both sides )
x² + 5x - 36 = 0 ← in standard form
(x + 9)(x - 4) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 9 = 0 ⇒ x = - 9
x - 4 = 0 ⇒ x = 4
However, x > 0 ⇒ x = 4
Answer:
m = 160
p = 90
w = 10
z = 80
y = 10
Step-by-step explanation:
Answer:
I would need to see the rectangles and there areas to answer that sorry
G(-4) = 4^2 + 3(-4) - 2
16 - 12 - 2
4 - 2
answer: 2
