4 years ago

What is the rotational symmetry of a rectangle

Mathematics

1 answer:

Fudgin [204]4 years ago

6 0

Order 2 rectangle has only 2

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If f(x) = 1/6 x-8, then f^-1(x)=

bezimeni [28]

Answer:

f^-1(x) is 6x + 48

f(x) = 1/6x - 8

To find f^-1(x) equate f(x) to y

That's

f(x) = y

y = 1/6x - 8

Next interchange the terms

We have

x = 1/6y - 8

Make y the subject

Multiply through by 6

We have

6x = y - 48

y = 6x + 48

Therefore f^-1(x) is 6x + 48

Hope this helps you

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( a² + 5a - 3 ) - ( 2a² - 4a + 3 )

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This is the answer

Step-by-step explanation:

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