Answers:
1.)
C - Final exams: midterm = Q3 92 - Q1 80 = 12 and finals = Q3 85 - Q1 78 = 7, so finals exam has the smaller IQR.
2.)
B - exam median is much higher than the class median: refer to the attached image of class and exam box and whisker graph
3.)
A - <span>
IQR is a better measure of spread for movies than it is for basketball games: because the data for movies are quite wide or apart from each other than the data in the basketball games
4.)
A - </span><span>
mean for April is higher than October's mean: mean in April is 67 and mean in October is 60
5.)
A - </span><span>
Neither data set has suspected outliers: meaning there's no data that is further apart from the group or set
6.)
B - </span>
There is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical
<span>
7.)
C - </span>
college spread is best described by the IQR. The high school spread is best described by the standard deviation: this is because of the wide range of data in the college than the data in the high school.
See picture of graph for answer:
Divide 13 into 29:
2.230769230769....
13 ) 29.0000000
26
—-
3 0 this remainder repeats 6 steps further down
2 6
——
40
39
——
100
91
——
90
78
—
120
11 7
—-
30 which will lead to a recurring decimal because we had remainder 3 at the beginning
Answer:
The explicit formula of that sequence is T - 5
Step-by-step explanation:
Let T represent each term in the sequence. So now try replacing T with each term in the sequence. Like this ;
7 - 5 = 2
2 - 5 = -3
-3 - 5 = -8
hope this helps