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blsea [12.9K]
3 years ago
10

Question 83 pts

Mathematics
1 answer:
8_murik_8 [283]3 years ago
4 0

Answer:

Ummm I dont know what subject it is so i will guess 2.3?

Step-by-step explanation:

I'm Sorry im really useless

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Expand and simplify (k-3)^7
nikklg [1K]
There are a couple of ways you can solve this. You can write it out like
(K-3)(K-3)(K-3)(K-3)(K-3)(K-3)(K-3)
And pretty much use the foil method
Or you can use the binomial theorem (google it if you dont know)
The solution should be:
(K^7) - 21(k^6) + 189(k^5) - 945(k^4) + 2835(k^3) - 5103(k^2) + 5103k - 2187
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3 years ago
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Vermont had 3 inches of snow on the ground before the sun melted 2 inches. The next storm tripled the amount on the ground. The
Finger [1]
The answer to the question is 2 and 1/2 left on the ground.
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I think of a number take away one and multiply the result by three but using x as your unknow
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I think of a number, (55) = my x. -1 = 54 x 3 = 162.
4 0
3 years ago
I need help on this homework question please
zheka24 [161]

(a) In functional notation, you are asked for C(600).

For this, put 600 where t is in the functional notation C(t).

(b) The value multiplying 8 is 0.5 when the exponent of 0.5 is 1. That is

... t/5730 = 1

Multiplying by 5730 gives

... t = 5730

It will take 5730 years for half the Carbon 14 to be gone.

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Or, you can recognize a fraction is 1 when its numerator is the same as its denominator. That is t/5730 = 5730/5730 = 1 when t=5730.

3 0
3 years ago
A shopper paid $2.52 for 4.5 pounds of potatoes, $7.75 for 2.5 pounds of broccoli and $2.45 f0r 2.5 pounds of pears. What is the
denis23 [38]
Unit rate refers to how much the buyer paid per unit. Let’s do the math:

$2.52 for 4.5 pounds of potatoes
Divide $2.52 by 4.5
The shopper paid 56 cents per pound of potatoes.
Now $7.75 spent for 2.5 pounds of broccoli.
Divide $7.75 by 2.5.
The shopper paid $3.10 for each pound of broccoli.
Last $2.45 for 2.5 pounds of pears.
The shopper will spend 98 cents per pounds of pears.
Please vote my answer brainliest! Thanks.
4 0
4 years ago
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