No, 4/10 is equal to 0.40 and not 0.45 since 4/10 goes in tens.
Since the problem is given all the total walking distance, the first thing we are going to do is find the total distance in the map:


Now that we have the distance in the map, we can establish a ratio between the walking distance and the distance in the map:

We can conclude that each inch the map represents 0.5 miles of walking distance.
1. NIL
2. ZERO
3. OH
4. NOUGHT
5. LOVE
Hope this helps!
Hey there! :)
Answer:
C. BC = 39 units.
Step-by-step explanation:
Use the Pythagorean theorem to solve for BC. Let BC = c, AB = a, and AC = b.
c² = a² + b²
c² = 15² + 36²
Square and simplify:
c² = 225 + 1296
c² = 1521
c = √1521
c = 39 units.
Therefore:
BC = 39 units.

he then turns around and grabs that money and sticks it for another 9 years,

add both amounts, and that's how much is for the whole 21 years.