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3 years ago

8

What is the vertex of g(x)=8x^2-64x

2 answers:

Mama L [17]3 years ago

8 0

<span>The (x,y) point of the vertex is usually labelled as:
Vertex = (h, k)
h = -b / 2a
h = --64 / 2*8
h = 64 / 16
</span><span>h = 4

</span>
<span>To get “k”, input the “h” value into the equation.
<span>k = 8*(4^2) -64*4
</span> <span>k = 8*(4^2) -64*4
</span><span>k = 128 -256
</span><span>k = -128
</span></span><span>Vertex = (4, -128)

</span>

Shkiper50 [21]3 years ago

5 0

Answer:

Vertex = (4, -128)

Step-by-step explanation:

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A sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters. Give a point est

liq [111]

Answer:

$s^2 = \frac{(1.48-1.502)^2 +(1.45-1.502)^2 +(1.54-1.502)^2 +(1.52-1.502)^2 +(1.52-1.502)^2}{5-1} =0.00132$

And for the deviation we have:

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And that value represent the best estimator for the population deviation since:

$E(s) =\sigma$

Step-by-step explanation:

For this case we have the following data:

1.48,1.45,1.54,1.52,1.52

The first step for this cae is find the sample mean with the following formula:

$\bar X =\frac{\sum_{i=1}^n X_}{n}$

And replacing we got:

$\bar X= \frac{1.48+1.45+1.54+1.52+1.52}{5} = 1.502$

And now we can calculate the sample variance with the following formula:

$s^2 =\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

And replacing we got:

$s^2 = \frac{(1.48-1.502)^2 +(1.45-1.502)^2 +(1.54-1.502)^2 +(1.52-1.502)^2 +(1.52-1.502)^2}{5-1} =0.00132$

And for the deviation we have:

$s= \sqrt{0.00132}=0.0363$

And that value represent the best estimator for the population deviation since:

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Read 2 more answers

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postnew [5]

260/400=0.65
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lilavasa [31]

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