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Elden [556K]
3 years ago
15

Please help!!!! I need help with this one problem I don't really understand.

Mathematics
1 answer:
gladu [14]3 years ago
7 0
T=10 + 0.20b
Total cost: 14.20
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Consider the line 7x+9y=5
alisha [4.7K]

Answer:

The slope of a line parallel to this line will be: -7/9

The slope of the perpendicular line will be:

\frac{-1}{\frac{-7}{9}}=\frac{9}{7}

Step-by-step explanation:

We know the slope-intercept form

y=mx+b

Here,

  • m is the slope
  • b is the y-intercept

Given the equation

7x+9y=5

simplifying to write in the lope-intercept form

y=-\frac{7}{9}x+\frac{5}{9}

Thus, the slope of the line is: -7/9

The slope of a line parallel to the line:

We have already determined that the slope of the line is: -7/9

  • We know that the parallel lines have the same slope.

Thus, the slope of a line parallel to this line will be: -7/9

The slope of a line perpendicular to the line:

We have already determined that the slope of the line is: -7/9

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line.

Thus,  the slope of the perpendicular line will be:

\frac{-1}{\frac{-7}{9}}=\frac{9}{7}

4 0
3 years ago
A right cone has an altitude of 4 units and a base diameter of 6 units. What is it’s lateral area?
fenix001 [56]

Answer:

Lateral area  =

pi *  (radius) * √ [ height ^2  + radius^2 ]  =

pi *  ( 4 )  * √ [  4^2 + 3^2 ]  =

pi * ( 4 ) * √25  =

pi * ( 4 ) * (5 )  =

20 pi  units^2  ≈   62.8 units^2

Step-by-step explanation:

4 0
3 years ago
A group pre-orders 8 tickets for a sightseeing tour, even though they don't have the money to pay for them yet. Each ticket cost
katen-ka-za [31]
Answer: -$266

Explanation: -32x8 because of 8 tickets, add 10 to the total debt because of the fee.
7 0
3 years ago
What is the cube root for 3000??
Alona [7]
\sqrt[3]{3000}=\sqrt[3]{1000\times3}=\sqrt[3]{1000}\times\sqrt[3]3=10\sqrt[3]3
4 0
3 years ago
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Please help me !!!!!
notka56 [123]

Answer:

the answer is 12

Step-by-step explanation:

8 0
3 years ago
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