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Vadim26 [7]
2 years ago
10

Find the 32nd term of the arithmetic sequence 32, 29, 26, 23, ...

Mathematics
1 answer:
Zinaida [17]2 years ago
3 0

Answer:

-55

-61

064

63

Step-by-step explanation:

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MArishka [77]

Answer:

1250 p² x¹² y³z⁶m⁵

Step-by-step explanation:

5x²y³z⁵m²(-2p²m³zx⁴)(-5x²)³

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1250 p²x¹²y³z⁶m⁵

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%20%7B%205%20x%20%5E%20%7B%202%20%7D%20-%2029%20x%20-%206%20%7D%20%7B%203%20x%20%5E%20%
olganol [36]

Answer:

Step-by-step explanation:

Vertical Asymptote: x=2Horizontal Asymptote: NoneEquation of the Slant/Oblique Asymptote: y=x 3+23 Explanation:Given:y=f(x)=x2−93x−6Step.1:To find the Vertical Asymptote:a. Factor where possibleb. Cancel common factors, if anyc. Set Denominator = 0We will start following the steps:Consider:y=f(x)=x2−93x−6We will factor where possible:y=f(x)=(x+3)(x−3)3x−6If there are any common factors in the numerator and the denominator, we can cancel them.But, we do not have any.Hence, we will move on.Next, we set the denominator to zero.(3x−6)=0Add 6 to both sides.(3x−6+6)=0+6(3x−6+6)=0+6⇒3x=6⇒x=63=2Hence, our Vertical Asymptote is at x=2Refer to the graph below:enter image source hereStep.2:To find the Horizontal Asymptote:Consider:y=f(x)=x2−93x−6Since the highest degree of the numerator is greater than the highest degree of the denominator,Horizontal Asymptote DOES NOT EXISTStep.3:To find the Slant/Oblique Asymptote:Consider:y=f(x)=x2−93x−6Since, the highest degree of the numerator is one more than the highest degree of the denominator, we do have a Slant/Oblique AsymptoteWe will now perform the Polynomial Long Division usingy=f(x)=x2−93x−6enter image source hereHence, the Result of our Long Polynomial Division isx3+23+(−53x−6)

4 0
2 years ago
Please help I will give a brainliest!!
lisov135 [29]

Answer:

True!!

Step-by-step explanation:

5 0
3 years ago
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saw5 [17]

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hope these help........

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