A nonlinear system of equation is a system of equation that has at list one nonlinear equation
A nonlinear system of equations that has one linear function that never intersects the quadratic function has; <u>No solution</u>
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The reason the option selected for the number of solutions is correct is as follows;
Required:
The number of solutions a system of nonlinear equations that do not intersect have
Solution:
The given system of equation is presented as follows;
Linear function: f(x) = m·x + c
Quadratic function: f(x) = a·x² + b·x + c
Given that the linear function never touches the quadratic function, we have;
a·x² + b·x + c ≠ m·x + c
Therefore, the equations are never equal hand they have no common solution
Therefore, the correct option is <u>No solution</u>
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Learn more about nonlinear system of equations here:
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Answer:
6 + 2(x +4) = 0.5(3 - x)
Not sure what your answer choices said considering the formatting, but the question itself results in the expression above.
5x/2 = 10/11
55x = 20
x = 4/11
**Not sure if I did this right I think I did

The only order pairs among the given options that represent a function is :
- (9 , -3) , (9 , -1) , (9 , -1)
Because : To be a function, every element of domain (x) can have only one unique value y, and if we get more than two values of y for same x, it isn't a function at all.
Answer:
6√3 ±3 ≈ {7.392, 13.392}
Step-by-step explanation:
The length of AB is the long side of a right triangle with hypotenuse CD and short side (AC -BD). The desired radius values will be half the length of EF, with AE added or subtracted.
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<h3>length of AB</h3>
Radii AC and BD are perpendicular to the points of tangency at A and B. They differ in length by AC -BD = 12 -9 = 3 units.
A right triangle can be drawn as in the attached figure, where it is shaded and labeled with vertices A, B, C. Its long leg (AB in the attachment) is the long leg of the right triangle with hypotenuse 21 and short leg 3. The length of that leg is found from the Pythagorean theorem to be ...
AB = √(21² -3²) = √432 = 12√3
<h3>tangent circle radii</h3>
This is the same as the distance EF. Half this length, 6√3, is the distance from the midpoint of EF to E or F. The radii of the tangent circles to circles E and F will be (EF/2 ±3). Those values are ...
6√3 ±3 ≈ {7.392, 13.392}