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Digiron [165]
3 years ago
10

Given the following rectangle: Solve for x. 10x - 43 3x + 6 (The answer is not 27)

Mathematics
1 answer:
____ [38]3 years ago
8 0

Answer:

<h2><em><u>X = 2</u></em></h2>

Step-by-step explanation:

10x - 43: x = 2

3x+6: x = 2

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Please help me with both of these.
Andru [333]
All i know is that the first one is an integer i think.
3 0
3 years ago
A submarine lies 3 kilometers from the path of a target ship. The sub’s torpedoes have a range of 5 kilometers. For what distanc
aev [14]

The distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

Explanation:

The submarine lies 3 km from the target ship.

Let B denotes the target ship and C denotes the submarine.

Let AC denotes the the target ship would be within the range of the torpedoes.

The image attached below illustrates that the distance between submarine and the target ship and the range of the torpedoes.

Let BC denotes the distance between the target ship and the submarine. Let AC denotes the range of the torpedoes.

To determine the length of AB, let us use Pythagorean theorem,

AC^{2} =AB^{2} +BC^{2}

Substituting the values of BC = 3 and AC = 5, we have,

5^{2} =AB^{2} +3^{2}

Squaring the terms, we get,

25 =AB^{2} +9

Subtracting both sides by 9, we have,

16 =AB^{2}

Taking square root on both sides,

AB = 4

Thus, the distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

5 0
4 years ago
After placing the compass' point on one end of the line segment and striking an arc above and below that segment, what is the ne
S_A_V [24]
Ill say, C) Place the compass' point on the other end of the segment.
4 0
3 years ago
Read 2 more answers
MATCHING GRAPHS! which ones which!! pls help ill award branliest
lisov135 [29]

Answer:

Its A and B i beleive.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Need answer ASAP!!<br> Find the area of the shaded region.
qwelly [4]

Answer:

(5x² +7x -26) units²

Step-by-step explanation:

\boxed{area \: of \: rectangle = length \times breadth}

Area of shaded region

= Area of larger rectangle -area of smaller rectangle

Area of larger rectangle

= (3x -4)(2x +2)

= 3x(2x) +3x(2) -4(2x) -4(2) <em>(</em><em>Expand</em><em>)</em>

= 6x² +6x -8x -8

= 6x² -2x -8

Area of smaller rectangle

= (x -6)(x -3)

= x² -3x -6x +18 <em>(</em><em>Expand</em><em>)</em>

= x² -9x +18

Area of shaded region

= 6x² -2x -8 -(x² -9x +18)

= 6x² -2x -8 -x² +9x -18

= 5x² +7x -26

4 0
3 years ago
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