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Daniel [21]
3 years ago
10

Use partial quotients to solve 504 divide 14

Mathematics
1 answer:
miv72 [106K]3 years ago
5 0

Answer:

Perform the following division using partial quotients: 504 ÷ 14:

To reduce the numerator, we will be multiplying the denominator by factors of 10, 5, 2, and 1

Step-by-step explanation:

1 4| 5 0 4

2 8 0 20 <---- 20 x 14 = 280

2 2 4 <---- 504 - 280 = 224

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10 <---- 10 x 14 = 140

8 4 <---- 224 - 140 = 84

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10

8 4

7 0 5 <---- 5 x 14 = 70

1 4 <---- 84 - 70 = 14

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10

8 4

7 0 5

1 4

1 4 1 <---- 1 x 14 = 14

0 <---- 14 - 14 = 0

Our partial quotients add up as follows:

20 + 10 + 5 + 1 = 36

I hope it helps plz Mark me brainliest:)

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Use the quadratic formula to solve x^2+8x+9=0
Tju [1.3M]
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Solve for x over the real numbers:
x^2 + 8 x + 9 = 0

x = (-8 ± sqrt(8^2 - 4×9))/2 = (-8 ± sqrt(64 - 36))/2 = (-8 ± sqrt(28))/2:
x = (-8 + sqrt(28))/2 or x = (-8 - sqrt(28))/2

sqrt(28) = sqrt(4×7) = sqrt(2^2×7) = 2sqrt(7):
x = (2 sqrt(7) - 8)/2 or x = (-2 sqrt(7) - 8)/2

Factor 2 from -8 + 2 sqrt(7) giving 2 (sqrt(7) - 4):
x = 1/22 (sqrt(7) - 4) or x = (-2 sqrt(7) - 8)/2

(2 (sqrt(7) - 4))/2 = sqrt(7) - 4:
x = sqrt(7) - 4 or x = (-2 sqrt(7) - 8)/2

Factor 2 from -8 - 2 sqrt(7) giving 2 (-sqrt(7) - 4):
x = sqrt(7) - 4 or x = 1/22 (-sqrt(7) - 4)

(2 (-sqrt(7) - 4))/2 = -sqrt(7) - 4:

Answer: x = sqrt(7) - 4 or x = -sqrt(7) - 4_____________________________________________________

Solve for x:
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Subtract 9 from both sides:
x^2 + 8 x = -9

Add 16 to both sides:
x^2 + 8 x + 16 = 7

Write the left hand side as a square:
(x + 4)^2 = 7

Take the square root of both sides:
x + 4 = sqrt(7) or x + 4 = -sqrt(7)

Subtract 4 from both sides:
x = sqrt(7) - 4 or x + 4 = -sqrt(7)

Subtract 4 from both sides:
Answer:  x = sqrt(7) - 4 or x = -4 - sqrt(7)
4 0
3 years ago
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