A.) When p = $33, q = (343 - 33)^2/100 = 961 units.
q'(p) = -(343 - p) / 50
q'(33) = -(343 - 33)/50 = -6.2
Price elasticity of demand = price / quantity * q'(p) = 33/961 * -6.2 = -0.2129
b.) Revenue = quantity * price = p(343 - p)^2/100
For maximum revenue, dR/dp = 0
-2p(343 - p)/100 + (343 - p)^2/100 = 0
-686p + 2p^2 + 117649 - 686p + p^2 = 0
3p^2 - 1372p + 117649 = 0
p = 343 or p = 114.33
For maximum revenue, he should sell for $114.33
c.) Maximum Revenue = 114.33(343 - 114.33)^2 / 100 = $59,783
C es la respuesta a la pregunta
When solving a problem like this you can start with either ys are yz. To make it simple, lets start with ys, you are going to divide s underneath at the y, then do it the other side as which Will turn the equation into y+yz=x/z.Then you're going to do the same thing with yz making the equation y+y=x/z+s. Then add the 2 y's, to get 2y=x/z+s, Then for the final step you are going to divide 2 on both sides making the answer
So it would be a,b because it like that
(3x+4)(2x+1)
If the question asks you to find roots/solutions:
3x + 4 = 0
3x = -4
x = -1.33333333
2x + 1 = 0
2x = -1
x = -0.5