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Natasha2012 [34]
3 years ago
9

Jack bought 50 lbs of clay for his art projects. He used 13.2 lbs to make a sculpture, and 0.72 lbs for each mug. How many mugs

did Jack make if he had 28.88 lbs of clay left over?
Please help me I really need the answer I have to do 6 more assignments and Helping me would really help me finishing.​
Mathematics
1 answer:
KIM [24]3 years ago
3 0

Given :

Jack bought 50 lbs of clay for his art projects. He used 13.2 lbs to make a sculpture, and 0.72 lbs for each mug.

To Find :

How many mugs did Jack make if he had 28.88 lbs of clay left over.

Solution :

Clay required to make 1 mug, r = 0.72 lbs.

Amount of clay left after making sculpture is, T = 28.88 lbs.

Now, number of clay mug Jack can make is :

n = \dfrac{28.88}{0.72}\\\\n= 40.11

Since, number of mug cannot be in decimal, so we take the floor value.

Therefore, number of mug that can be prepared is 40 .

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Beverly drove from the Atlantic City to New York she drove 284 miles at a constant speed of 58 mph how long did it take Beverly
kondor19780726 [428]

Answer:

Find the number of hours by dividing the distance by mph. The number of hours will be to the left of the decimal point:

284 miles / 58 mph

= 4.896551724

= 4 hours

2) Find the number of minutes by multiplying what is remaining from step 1 by 60 minutes. The minutes will be to the left of the decimal point:

0.896551724 x 60

= 53.79310344

= 53 minutes

3) Find the number of seconds by multiplying what is remaining from step 2 by 60 seconds. The seconds will be to the left of the decimal point:

0.79310344 x 60

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The answer is 4 hours 53 minutes and 47 seconds approx

3 0
3 years ago
If a 25 ft rope is cut into two sections with one section 4 times as long as the other section, how long is the shorter piece?
DaniilM [7]
X = short section of rope
4x = longer section of rope

x + 4x = 25
5x = 25
x = 5

…or in other words the shorter piece of rope is 5 feet long
7 0
3 years ago
The function ​f(x,y)=2x + 2y has an absolute maximum value and absolute minimum value subject to the constraint 9x^2 - 9xy + 9y^
deff fn [24]

Answer:

the minimum is located in x = -5/3 , y= -5/3

Step-by-step explanation:

for the function

f(x,y)=2x + 2y

we define the function g(x)=9x² - 9xy + 9y² - 25  ( for g(x)=0 we get the constrain)

then using Lagrange multipliers f(x) is maximum when

fx-λgx(x)=0 → 2 - λ (9*2x - 9*y)=0 →

fy-λgy(x)=0 → 2 - λ (9*2y - 9*x)=0

g(x) =0 → 9x² - 9xy + 9y² - 25 = 0

subtracting the second equation to the first we get:

2 - λ (9*2y - 9*x) - (2 - λ (9*2x - 9*y))=0

- 18*y + 9*x + 18*x - 9*y = 0

27*y = 27 x  → x=y

thus

9x² - 9xy + 9y² - 25 = 0

9x² - 9x² + 9x² - 25 = 0

9x² = 25

x = ±5/3

thus

y = ±5/3

for x=5/3 and y=5/3 →  f(x)= 20/3 (maximum) , while for x = -5/3 , y= -5/3 →  f(x)= -20/3  (minimum)

finally evaluating the function in the boundary , we know because of the symmetry of f and g with respect to x and y that the maximum and minimum are located in x=y

thus the minimum is located in x = -5/3 , y= -5/3

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