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Katyanochek1 [597]
3 years ago
7

The volume of air in a balloon is represented by the function v(n) = ne?, where r is the radius of the balloon, in

Mathematics
1 answer:
Sergio [31]3 years ago
7 0

Answer:

When V is composed with r, the composite function is StartFraction 1 Over 48 EndFraction pi t Superscript 6

V(r(6)) shows that the volume is 972π inches cubed when the radius increases to 6 inches.

Step-by-step explanation:

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If z^2+1/z^2=11 , find the value of z^3-1/z^3,using only the positive value of z-1/z
vredina [299]
Hello,

Let's assume

t=z- \dfrac{1}{z} \\\\

t^2=z^2-2+ \dfrac{1}{z^2}= 11-2=9==\ \textgreater \ t=3\\\\

t^3=z^3-3z^2* \dfrac{1}{z} +3z* \dfrac{1}{z^2} - \dfrac{1}{z^3} \\\\
=z^3 - \dfrac{1}{z^3} -3(z-\dfrac{1}{z})\\\\
z^3 - \dfrac{1}{z^3}=t^3+3t=3^3+9=27+9=36



7 0
3 years ago
Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC
jarptica [38.1K]

We are given

△ABC, m∠A=60° m∠C=45°, AB=8

Firstly, we will find all angles and sides

Calculation of angle B:

we know that sum of all angles is 180

m∠A+ m∠B+m∠C=180

we can plug values

60°+ m∠B+45°=180

m∠B=75°

Calculation of BC:

we can use law of sines

\frac{AB}{sin(C)}=\frac{BC}{sin(A)}

now, we can plug values

\frac{8}{sin(45)}=\frac{BC}{sin(60)}

BC=\frac{8}{sin(45)} \times sin(60)

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Calculation of AC:

\frac{AB}{sin(C)}=\frac{AC}{sin(B)}

now, we can plug values

\frac{8}{sin(45)}=\frac{AC}{sin(75)}

AC=\frac{8}{sin(45)} \times sin(75)

AC=10.928

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p=AB+BC+AC

we can plug values

p=10.928+8+9.798

p=28.726

Area:

we can use formula

A=\frac{1}{2}AB \times AC \times sin(A)

now, we can plug values

A=\frac{1}{2}8 \times 10.928 \times sin(60)

A=37.85570...............Answer

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3 years ago
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salantis [7]

Answer:

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Step-by-step explanation:

2x › 5 (buy at least 4)

so you can just start plugging numbers in.

I used 5, 5 times 2 is 10 which is 5 more that 5, which does met the quota.

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2 years ago
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Answer:

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