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3 years ago

!!!!!please help!!!!!!!!

Mathematics

1 answer:

lara31 [8.8K]3 years ago

3 0

From Plato
30e-0.12t less than or equal to M
40e-0.18t less than or equal to M
Step-by-step explanation:
It is given that compound A decays at a rate of 12% per week, and compound B decays at a rate of 18% per week. Since the rates represent decay, the r-value is negative. A decay rate of 12% is represented by an r-value of -0.12, and a decay rate of 18% is represented by an r-value of -0.18.
The initial amount of compound A is 30 grams and the initial amount of compound B is 40 grams. Substitute the initial amounts of each compound and their respective decay rates into the system of inequalities.
The following system of inequalities can be used to determine when the remaining mass of the two compounds, M, will be the same, after t weeks.

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2 years ago

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gtnhenbr [62]

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Step-by-step explanation:

Formula to find the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ = sample proportion.

z* = Critical value

n= Sample size.

Let p be the true proportion of GSU Juniors who believe that they will, immediately, be employed after graduation.

Given : Sample size = 3597

Number of students believe that they will find a job immediately after graduation= 3099

Then, $\hat{p}=\dfrac{3099}{3597}\approx0.8616$

We know that , Critical value for 99% confidence interval = z*=2.576 (By z-table)

The 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation will be

$0.8616\pm(2.576)\sqrt{\dfrac{0.8616(1-0.8616)}{3597}}$

$0.8616\pm (2.576)\sqrt{0.0000331513594662}$

$\approx0.8616\pm0.0148\\\\=(0.8616-0.0148,\ 0.8616+0.0148)=(0.8468,\ 0.8764)$

Hence, the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. = (0.8468, 0.8764)

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3 years ago