First I am going to assume that these are both right triangles based off of look and because it is much easier. Without it you have to use law of sines or law of cosines...
So to find x you must first find y which can be done simply by using the pythagorean theorem. This theorem is defined as the sum of the squared legs is equal to the sum of the hypotenuse or x^2 + y^2 = z^2
If we substitute in the known values 16^2 + y^2 = 20^2 and solve for y we get that y = sqrt(20^2 - 16^2), this then simplifies to y = 12
Finding x is much more annoying, the easiest way I can immediately see is to find the upper angles by doing sin(16/20) and then 90 - sin(16/20) since the complementary angle is the one you want. I don't have a calculator or a trig table with me right now but I will tell you that x will be equal to 12 ÷ the inverse cosine of the angle (90degrees - sin(16/20)).
I am pretty sure the answer is D though because we know for sure y = 12 and x has to be greater than y because the hypotenuse must be larger than both legs. It could be E but you won't know unless you do the math for x. So it is either D or E but I would be surprised if a Professor made you do all of the work just to say it doesn't work...
A googol is bigger than a billion.
For a logarithmic function, we have a restriction on the domain.
Since log(0) isn't defined, we say that there is an asymptote at x = 0.
Thus, for the regular logarithmic function y = log(x), x > 0.
We can then say (x + 4) > 0, since that's when the function of a logarithm is defined as.
x + 4 > 0
x > -4
Thus, the domain of the logarithmic function is x > -4, where x is a real integer.
Let's call the aces 
for hearts, diamonds, clubs and spades. So, 
are red and [ted] c, s[/tex] are black.
Since the first card is replaced, the two picks are identical. This means that the sample space is given by all the possible couple
There are 16 such couples (we have four choices for the first card, and the same four choices for the second card). Now let's compute the odds in our favour to deduce the probability of winning:
If we want a player to draw two card of the same colour, the following couples are good:
so 8 possible couples over 16. This means that the probability that a player draws two cards of the same color is 8/16 = 1/2.
Similarly, the probability of drawing a red ace first and then a black ace is represented by the following couples:
which are 4 over the same 16 as above, thus leading to a probability of 4/16 = 1/4.
