Given that, the time (t) taken to complete a journey varies directly as the distance (d) and inversely as the average speed (s).
Hence, we can set an equation as following:
t = k\frac{d}{s}
Other information is that it takes 3 hours to complete a 280km trip at 80km/h.
So, plug in t = 3, d = 280 and s = 80 in the above equation to get the value of k. Therefore,
![3=k \frac{280}{80} [/tex3 = k* 3.5[tex] \frac{3}{3.5} =\frac{k*3.5}{3.5}](https://tex.z-dn.net/?f=%203%3Dk%20%5Cfrac%7B280%7D%7B80%7D%20%5B%2Ftex%3C%2Fp%3E%3Cp%3E3%20%3D%20k%2A%203.5%3C%2Fp%3E%3Cp%3E%5Btex%5D%20%5Cfrac%7B3%7D%7B3.5%7D%20%3D%5Cfrac%7Bk%2A3.5%7D%7B3.5%7D%20)
Divide each sides by 3.5.
k = 0.857142857
So, k = 0.857
Now we need to find the time when d= 546 and s = 65. So, plug in these values in the above equation to get the value of t. Hence,
t = 0.857*\frac{546}{65}
= 0.857 * 8.4
= 7.1988
= 7 hours ( Rounded to nearest integer).
So, it will take 7 hours.
Hope this helps you!
The value<span> of </span>y<span> has changed at a </span>much<span> greater rate. </span>If<span> the x-axis represents time and the </span>y<span>-axis distance, as is the case in </span>many<span> applications, then the rate of </span>change<span> of </span>y<span> with respect to x -- of distance with respect to time -- is called speed or velocity.</span>
If 13% of 100 is 13, than 13% of 100 million is 13 million. And multiplying two on both sides, we get that 13% of 200 million is 26 million. If we take it the other way, we get that 13% of 50 million is 6.5 million. As 6.5 million + 25 million is 31.5 million, this is our answer.
2r² − 28r + 38 = 0
2 (r² − 14r) = −38
2 (r² − 14r + 49) = −38 + 2(49)
2 (r − 7)² = 60
(r − 7)² = 30
the answer is 2(r-7)² =60
It would be between 2.77 and 2.79
