All categories

3 years ago

Find a. Round to the nearest tenth

Mathematics

1 answer:

Drupady [299]3 years ago

8 0

Answer:

a = 2.14cm to the nearest 10th =2.1

Step-by-step explanation:

your welcome :)

You might be interested in

If m = 5 and n = -2, evaluate 3m - 4n and n2 - m and find the product of the two expressions.

ddd [48]

Hence the correct answer is C) -23

Further explanation:

We have to put the values of m and n into both expression first separately and then multiply the answers.

Given expressions are:

$Exp\ 1:3m-4n\\Exp\ 2: n^2-m$

The values are:

$m=5\\n=-2$

Putting the values in expression 1:

$3m-4n\\=3(5)-4(-2)\\=15+8\\=23$

Putting the values of m and n in second expression

$n^2-m\\=(-2)^2-5\\=4-5\\=-1$

Multiplying both expressions:

$(3m-4n)(n^2-m)=23* (-1)=-23$

Hence the correct answer is C) -23

Keywords: Polynomials, Putting values in expressions

Learn more about polynomials at:

#LearnwithBrainly

8 0

3 years ago

Using the quadratic formula to solve 5x = 6x- - 3, what are the values of x?

goldfiish [28.3K]

Answer:

x= -3

Step-by-step explanation:

Solve the rational equation by combining expressions and isolating the variable x.

8 0

2 years ago

Read 2 more answers

Veronica is saving money to by a saddle for her horse that costs 175 . She plans to save $10 the first month and then increased

Anon25 [30]

You will start off with $175-$10=$165. Then you will take your $165 and divide by $15 to get the answer. $165÷$15=11 months to save the money.

6 0

3 years ago

$1,000 for 40 years at 8% annual simple interest

bekas [8.4K]

Answer:

$3200

Step-by-step explanation:

1000x40x8/100

pls make me brainlist

5 0

3 years ago

SOMEONE HELP ME PLEASE WITH THESE PROBLEMS AND PLEASE SHOW YOUR WORK FOR 50 points and BRAINLIEST THANK YOU

ELEN [110]

<u>Answer</u>:

13. $6x^7 y^7$ || 14. $\frac{25x^4}{y^6}$

<u>explanation</u>:

13.

$\frac{12x^9 y^5}{2x^2 y^-2}$

$6x^{9-2} y^{5--2}$

$6x^7 y^7$

14.

$(\frac{5y^{-3} }{x^{-2} } )^{2}$

$(\frac{5y^{-3} }{x^{-2} } )(\frac{5y^{-3} }{x^{-2} } )$

$\frac{\frac{25}{y^6}}{\left(x^{-2}\right)^2}$

$\frac{\frac{25}{y^{-6} }}{\left(x^{-4}\right)}$

$\frac{25x^4}{y^6}$

4 0

2 years ago

Read 2 more answers