first you have to find the triangle, then you can move to the actual question.
x+30+80 = 180
x+110 = 180
x+110 - 110 = 180-110
x =70
now you can go to the actual question.
y + 70 = 180
y+70- 70 = 180-70
y = 110
there is your answer. hope this is helpful
Answer: 16 men
32 women
38 children
Step-by-step explanation:
Let x represent the number of men in the group.
Let y represent the number if women in the group.
Let z represent the number of children in the group.
A group of 86 people consist of men women and children. This means that
x + y + z = 86 - - - - - - - - - - - - 1
There are twice as many women than there are men. It means that
x = y/2
There are 6 more children than there are women. This means that
z = y + 6
Substituting x = y/2 and z = y + 6 into equation 1, it becomes
y/2 + y + y + 6 = 86
multiplying through by 2, it becomes
y + 2y + 2y + 12 = 172
5y = 172 - 12 = 160
y = 160/5 = 32
x = y/2 = 32/2
x = 16
z = y + 6 = 32 + 6
z = 38
5+8x+6y-2y. i got that by adding like numbers/variables
Say you have this problem.
4x=2x-4
First you would combine your like terms.
4x = 2x-4
-2x=-2x-4
---------------
2x=-4
Next you would divide
2x =-4
÷ -4 =-4
--------------
x = 0.5
Distance from J to F = b
D from F to K = a
a^2+b^2=JK^2
D from K to G = a
D from G to L = b
a^2+b^2=KL^2
D from L to H = b
D from H to M = a
a^2+b^2=LM^2
D from M to E = a
D from E to J = b
a^2+b^2=MJ^2
For each side, I used the Pythagorean theorem (a^2+b^2=c^2) to find the length. Since every side of the quadrilateral squared (aka to the power of two) equals a^2+b^2, every side squared equals each other. So JK^2=KL^2=LM^2=MJ^2. If you take the square root of each side of the equal signs, you’re left with JK=KL=LM=MJ. In order for a quadrilateral to be a rhombus, each side must be equivalent. Each side in this quadrilateral is equivalent, therefore it is a rhombus.
