Answer:
6,4
Step-by-step explanation:
I'm not sure if 4 is correct but 6 definitely is. I hope this helps
When a function is shifted to the right by 1 unit it is moved towards the negative side so we would be adding -1 to the value of x. The function f(x) would be f(x-1). To determine the resulting function, we substitute to the parent function (x-1) to x. We do as follows:
<span>f (x) = x^3 + 2x^2 − 3x − 5
</span>f (x-1) = (x-1)^3 + 2(x-1)^2 − 3(x-1) − 5
f (x-1) = x^3 - 3x^2 + 3x - 1 + 2(x^2 - 2x + 1) - 3x + 3 - 5
f (x-1) = x^3 - 3x^2 + 2x^2 + 3x - 4x - 3x - 1 + 2 + 3 - 5
f (x-1) = <span>x^3 - x^2 - 4x - 1
Therefore, the correct answer is the last option.</span>
The second answer is 4 times as small as the first
The correct answer is:
b.) f(n) = 3 • (-2)^(n-1)
Further explanation:
Given sequence is:
3, -6, 12, -24, ...
We have to find the common ratio first.
Common ratio is the ratio between two consecutive terms of a geometric sequence.
It is denoted by r.
So,

General formula for geometric sequence is:

Putting the values of a1 and r

Hence,
The correct answer is:
b.) f(n) = 3 • (-2)^(n-1)
Keywords: Geometric Sequence, Explicit formula
Learn more about geometric sequence at:
#LearnwithBrainly
Answer:
The midpoint is (2 , 1)
Step-by-step explanation:
To find the midpoint, we have to add the corresponding coordinates
[(-5 , 3) + (3 , -1)] / 2
we separate into the corresponding
(-5 + 3) / 2 =
-2 / 2 = -1
(3 - 1) / 2 =
2 / 2 = 1
The midpoint is (2 , 1)