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3 years ago

How to solve fractagons

Mathematics

1 answer:

Law Incorporation [45]3 years ago

7 0

Answer:

By using cross multiplication

Step-by-step explanation:

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Change this root into a power.

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Answer:

3^2/5

Step-by-step explanation:

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3 years ago

Please help! solve.

IRINA_888 [86]

Answer:

x=11

Step-by-step explanation:

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3 years ago

A company produces remote-controlled helicopters. The company’s profit, in thousands of dollars, as a function of the number of

erma4kov [3.2K]

We simply substitute 6 into the equation:
f(6) = -2(6 - 4)² + 22
f(6) = 14

The company's profit is 14 thousand dollars
hope it helped :).

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3 years ago

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WILL MARK BRAINLIEST ANSWER!!!<br><br> 6. Find the measure of angle x.

ehidna [41]

Answer:

A: 71°

Explanation:

The interior angles of a triangle must always equal 180°.

We have two of the angles, and if we add them up and subtract it from 180°, we can get the missing angle.

49+60+x=180

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109+x=180

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3 years ago

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An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click

Sergeeva-Olga [200]

Answer:

A. $\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

B. $\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

Step-by-step explanation:

Given that:

An investment of Amount = $8000

earns at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A) Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

$A = Pe^{rt}$

where;

$A = (8000) \ e ^{0.7t}$

The instantaneous rate of change = $\dfrac{dA}{dt}$

$\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )$

$= 8000 \dfrac{d}{dt}e^{0.07 \ t}$

$\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}$

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 2 years; the instantaneous rate of change is:

$\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}$

$\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

$12000 = (8000)e^{0.07 \ t}$

$\dfrac{12000 }{8000}= e^{0.07 \ t}$

$1.5= e^{0.07 \ t}$

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 5.79

$\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}$

$\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

7 0

3 years ago

How to solve fractagons​

How to solve fractagons