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Yakvenalex [24]
3 years ago
9

In a rotation, what is the relationship between the distance from a point on the preimage to the center of rotation and the dist

ance from the corresponding point on the image to the center of rotation? A. half the distance B. same distance C. twice the distance D. three times the distance
Mathematics
2 answers:
aev [14]3 years ago
8 0
Answer: B. same distance

There is the same distance between the point on the preimage to the center of rotation and that of the distance from the corresponding point on the image to the center of rotation. There is change in the distance of the two. 

djyliett [7]3 years ago
8 0

Answer: B. same distance

Explanation:

The rotation consists on the angular motion of the points of the preimage.

Therefore, the center of rotation is fixed and each point is transported a number of degrees (counter-clockwise or clockwise), keeping fixed the distance from the center of rotation.

It is exactly like making a circle but you stop before completing the circle, when you have rotated the amount of degress (angle) desired.

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Tpy6a [65]

Answer:

A=147.03\text{ cm}^2

Step-by-step explanation:

The area for a parallelogram is given by the formula:

A=bh

Where b is the base length and h is the vertical height.

The base length is 16.9 while the vertical height is 8.7. Thus:

A=(16.9)(8.7)

Multiply using a calculator:

A=147.03\text{ cm}^2

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Step-by-step explanation:

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Answer:

Inequality Form:

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Interval Notation:

( 2 − √ 11 , 2 + √ 11 )

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Sally’s dance school had 60 students last year. This year there are only 48 students enrolled. By what percent did the enrollmen
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Answer:

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lianna [129]

Answer:

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Step-by-step explanation:

Given the expression

x^3-1

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\mathrm{Apply\:Difference\:of\:Cubes\:Formula:\:}x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)

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Thus, the factored form of x^3 -1 will be:

x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)

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