For this problem, you have to come up with two equations, one for each plan, and set them equal to each other to solve for how many minutes <span>of calls when the costs of the two plans are equal. Let's call the number of minutes "x." Remember the equation for slope-intersect form is:
</span>

<span>And we're trying to put in values for m and b.
So the first plan has a </span>$29 monthly fee and charges an additional $0.09 per minute. The $29 monthly fee will be our "b" in our slope-intersect equation because it won't be affected by our minutes "x." That means 0.09 is our "m" value because it will change with "x." So our equation for plan 1 is:

The second plan <span>has no monthly fee but charges 0.13 for each minute of calls. Because there is no monthly fee, there is no "b" this time. "m" will be 0.13. So our equation for plan 2 is"
</span>

Now we set our two equations equal to each other. "y" in the equation stands for the total cost of the plan. If the total costs are equal, then they have to be the same number, so we can put one of the equations for "y" into the other equation and solve for "x," our number of minutes:
Answer:
4... hope this will help
Step-by-step explanation:
Answer:
<em>41.8°, 138.2° and 401.8°</em>
Step-by-step explanation:
Given the expression;

Let P = sinx
The expression becomes;
3P²+4P - 4 = 0
Factorize
3P²+6P-2P - 4 = 0
3P(P+2)-2(P+2) = 0
3P-2 = 0 and P+2 = 0
P = 2/3 and -2
When P = 2/3
sinx = 2/3
x = arcsin 2/3
x = arcsin 0.6667
x = 41.8 degrees
Also if P = -2
sinx = -2
x = arcsin (-2)
x will not exist in this case
To get other values of x
sin is positive in the second quadrant
x = 180 - 41.8
x = 138.2°
x = 360+41.8
x = 401.8°
<em>Hence the values of x within the interval are 41.8°, 138.2° and 401.8°</em>
Answer:
Step 2 has error and step 4 has error.
Step-by-step explanation:
Here we can see that elimination method is applied to solve the system of equations for which -2 is multiplied both sides of equation first
-2(x+2y)=-2(10 which is correct
but in step 2
left side is -2x-4y and the right side is -10 which has to be -20 which makes this step wrong and this is the error made by student.
in Step 4 also ,value of the y has to be 5 but student plugged y =1 which is also error by student.
Correct solution is
-2x-4y= -20
2x+ 5y= 15
on adding ,we get
y = -5
plugging y =5 in equation x+2y= 10 ,we get x+2(-5) =10 ,we get x = 20
therefore (20,-5) is the solution
3. A.-2
4. B.2
Hope this helps