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Katyanochek1 [597]
3 years ago
9

Tom used 3/8 of a piece of ribbon for a kite tail. From the remaining 5/8 of the ribbon, he cut pieces to tie weights on the kit

e tail. Each tie was 1/12 of the whole ribbon. How many times did he cut?
Mathematics
1 answer:
Dmitry [639]3 years ago
7 0

Answer:

7.5

Step-by-step explanation:

Fraction used for kite = 3/8

Fraction of entire ribbon = 1/1

Fraction left after making kite :

Fraction left = 1 - 3/8 = (8 - 3) / 8 = 5/8

Fraction used as tie = 1/12

Number of ties obtainable from the fraction left :

Fraction of ribbon left ÷ fraction used as tie

5/ 8 ÷ 1/ 12

5/8 * 12 / 1

= 60 / 8

= 7.5

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Los profesores de un colegio tienen planeado mandar 6 boletines informativos al año a cada una de las 620 familias con estudiant
alekssr [168]

Answer:

14.88 resmas

Step-by-step explanation:

Los maestros de una escuela planean enviar 6 boletines al año a cada una de las 620 familias con estudiantes en la escuela.

Esto significa: El número total de boletines que recibe cada familia = 6 × 620 familias

= La escuela envía 3720 boletines cada año

Cada uno de los boletines necesita 2 hojas de papel.

1 boletín = 2 hojas de papel

3720 boletines =

Cruz multiplicar

3720 boletines × 2 hojas

= Se necesitan 7440 hojas de papel en un año

El papel se vende en resmas de 500 hojas.

¿Cuál es la cantidad mínima de resmas de papel necesarias para imprimir los boletines escolares en un año?

500 hojas de papel = 1 resma

7440 hojas de papel = y

Cruz multiplicar

500 × y = 7440 × 1

y = 7440/500

y = 14.88 resmas

La cantidad mínima de resmas de papel necesarias para imprimir los boletines escolares en un año es 1488 resmas

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