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3 years ago

PLEASE HELP WILL GIVE BRAINLIEST!!!!!!!!

2 answers:

6 0

use a = (v1-v2)/t so u would put 14 (initial velocity or v 1) - 6 (the v2) and divide all of that by 4 seconds to get 2m/s/s as your acceleration

Naddik [55]3 years ago

6 0

Acceleration = (change in speed) / (time for the change)

Change in speed = (ending speed) - (starting speed)

Change in speed = (14 m/s) - (6 m/s) = 8 m/s

Time for the change = 4 seconds

Acceleration = (8 m/s) / (4 sec)

Acceleration = (8/4) (m/s·s)

Acceleration = 2 m/s²

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One normal afternoon in undisclosed City X, the chocolate factory workers overload the Easter egg machine. A group of angsty tee

musickatia [10]

Answer:

The correct option is;

C. 1,715 m

Explanation:

We are given the information from the group of teen at the City edge

Time of arrival of explosion sound = 5 s after sighting

Time of sighting explosion = 5 s before hearing the boom

Speed of sound in air ≈ 343 m/s

Speed of light = 299,792 km/s

Therefore, distance covered by sound in 5 seconds is given by the following equation;

$Speed = \frac{Distance}{Time}$

$\therefore 343 \ m/s= \frac{Distance}{5 \, s}$

Hence Distance = 343 m/s × 5 s = 1715 m

To check, we compare the time it would take for the light to cover 1715 m

That is $Time = \frac{Distance}{Speed} = \frac{1715}{299,792,000} = 0.00000572 \, s$ which is instantaneous hence the distance can be approximated by the time duration for the speed of sound.

Therefore, the distance of the students from the factory is approximately 1,715 m

8 0

4 years ago

Two paths lead to the top of a big hill. One is steep and direct, while the other is twice as long but less steep. How much more

umka2103 [35]

Answer:

None.

Explanation:

Gravitational potential energy, depends only of the mass on which the gravity is doing work, and the displacement produced by this force.
As displacement depends only on the final and initial positions (in this case, the height of the hill), if we choose as our zero reference level the bottom of the hill, the change in gravitational potential energy will be as follows:

$\Delta U = U_{f} -U_{0} = m*g*h - 0 = m*g*h$

As we can see, the only value of distance involved is the height of the hill , so it is independent of the distance travelled.

6 0

4 years ago

A 2100 g block is pushed by an external force against a spring (with a 22 N/cm spring constant) until the spring is compressed b

Vilka [71]

Answer:

6.5e-4 m

Explanation:

We need to solve this question using law of conservation of energy

Energy at the bottom of the incline= energy at the point where the block will stop

Therefore, Energy at the bottom of the incline consists of the potential energy stored in spring and gravitational potential energy= $\frac{1}{2} kx^{2} +PE1$