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Maru [420]
2 years ago
8

A 45.0-kg sample of ice is at 0.00°C. How much heat is needed to melt it? For water, Lf=334 kJ/kg and Lv=2257 kJ/kg 

Physics
2 answers:
Aleonysh [2.5K]2 years ago
7 0

Heat required to change the phase of ice is given by

Q = m* L

here

m = mass of ice

L = latent heat of fusion

now we have

m = 45 kg

L = 334 KJ/kg

now by using above formula

Q = 45 * 334 * 10^3

Q = 1.5 * 10^7 J

In KJ we can convert this as

Q = 1.5 * 10^4 kJ

so the correct answer is D option

Vlad1618 [11]2 years ago
6 0
H=ml
H=334×45.0
Heat Energy= 15030kJ

or 1.50×10^4kJ

answer: D

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Answer:

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3 years ago
A laser emits two wavelengths (λ1 = 420 nm; λ2 = 630 nm). When these two wavelengths strike a grating with 450 lines/mm, they pr
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B) The overlap occurs at an angle of 34.9^{\circ}

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A)

The formula that gives the position of the maxima (bright fringes) for a diffraction grating is

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d sin \theta = m_1 \lambda_1

For laser 2,

d sin \theta = m_2 \lambda_2

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Since the position of the maxima in the two cases overlaps, then the term d sin \theta on the left is the same for the two cases, therefore we can write:

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B)

In order to find the angle at which the overlap occurs, we use the 1st laser situation:

d sin \theta = m_1 \lambda_1

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d=\frac{1}{N}=\frac{1}{450,000}=2.2\cdot 10^{-6} m

m_1 = 3 is the order of the maximum

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Solving for \theta, we find the angle of the maximum:

sin \theta = \frac{m_1 \lambda_1}{d}=\frac{(3)(420\cdot 10^{-9})}{2.2\cdot 10^{-6}}=0.572

So the angle is

\theta=sin^{-1}(0.572)=34.9^{\circ}

Learn more about diffraction:

brainly.com/question/3183125

#LearnwithBrainly

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