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dimulka [17.4K]
2 years ago
11

A javelin thrower is running at 7mph and throws her javelin at 18mph at an angle of 13o with the horizontal. Determine the resul

tant speed and direction of the javelin. i need the magnitude and the direction !!! HELP WILL MARK BRALIEST
Mathematics
1 answer:
RUDIKE [14]2 years ago
5 0
Will I get any points?
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The Jacksons went on a 700 mile trip. On the first day they drove 6 and 2/3 hours and on the second day the drove 5 and 3/4 hour
likoan [24]

Answer:

Step-by-step explanation:

Total number of miles is 700.

On the first day, they drove 6 and 2/3 hours. We would convert 6 and 2/3 hours to improper fraction. It becomes 20/3 hours. On the second day, they drove 5 and 3/4 hours. Converting to improper fraction, it becomes 23/4 hours. Total number of hours that they drove during the first two days is the sum of hours driven on the first day and hours driven on the Second day. It becomes

20/3 + 23/4 = (80 + 69)/12

= 149/12 hours

7 0
3 years ago
Can someone help me and write the answer in scientific notation <br> and show the steps
Juliette [100K]
8.05 x 10^8 - 9.16 x 10^6
= 10^6 (805 - 9.16)
= 795.84 x 10^6
= 7.9584 x 10^8
6 0
3 years ago
The price of a visit to the dentist is \$50$50dollar sign, 50. If the dentist fills any cavities, an additional charge of \$100$
Goshia [24]

Answer:

The expense of the visit to dental specialist is equivalent to (50+100n)

Step-by-step explanation:

7 0
2 years ago
The minute hand on a clock is 9 centimeters long and travels through an arc of 252 degrees every 42 minutes. To the nearest tent
kkurt [141]

Answer:

39.6 cm

Step-by-step explanation:

Applying

s = 2πrθ/360................ Equation 1

Where s = length of an arc or distance traveled by the minutes hand of the clock during the 42 munites, r = length of the minutes hand of the clock, θ = Angle traveled by the minute hand of the clock for every 42 minutes

From the question,

Given: r = 9 cm, θ = 252°

Constant: π = 22/7 = 3.14

Substitute these values into equation 1

s = (2×3.14×9×252)/360

s = 39.564

s = 39.6 cm

4 0
3 years ago
A hackberry tree has roots that reach a depth of
Degger [83]

Answer:

24.6967 meters

Step-by-step explanation:

The roots of the tree go 6 and 5 over 12 meters below the ground level.

Now, 6 and 5 over 12 meters is equivalent to 6.4167 meters.

Again the top of the tree is 18.28 meters high from the ground level.

Therefore, the total height of the tree from the bottom of the root to the top is  

(6.4167 +18.28) = 24.6967 meters (Answer)

5 0
3 years ago
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