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sammy [17]
2 years ago
14

In a dilation, what is preserved and what is altered?

Mathematics
1 answer:
fgiga [73]2 years ago
5 0

Answer:

A dilation preserves angle measures.

A dilation alters the length of line segments by the same proportion.

Step-by-step explanation:

A dilatation is a transformation that alters a figure's size while maintaining its shape and orientation. Each linear measure of the figure, such as a side length, is multiplied by the scale factor of a dilatation. A dilation is a transformation where all line segments' lengths are altered uniformly. While a dilatation can alter a figure's size, it cannot alter a figure's form. Dilations are not isometries as the figure's size changes.

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5k + 9 = 89.............
blsea [12.9K]

Answer:

k= 16

Step-by-step explanation:

89-9=80

80/5=16

16=k

5 0
2 years ago
Read 2 more answers
a local company uses 13 1/2 tons of paper in one week. It recycles about 1/3 of its waste. how many tons of paper does the compa
bogdanovich [222]

Answer:

4 1/2 tons of recycled paper

Step-by-step explanation:

13.5/3 = 4.5 or 4 1/2

3 0
2 years ago
Please help. I don’t know the answer.
atroni [7]
(y^12)/5

9/45=1/5
x^5/x^5=1
y^16/y^4=y^12
4 0
2 years ago
Read 2 more answers
Please help and explain I'll give u 12pts
White raven [17]

-7x² + 70x - 175

= -7(x² - 10x + 25)

= -7(x - 5)²

= -7(x + -5)²

Answer: -5

7 0
3 years ago
Find integra of xlnxdx
Mademuasel [1]

Answer:

\dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a <u>constant of integration</u>.

\boxed{\begin{minipage}{4 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\end{minipage}}

Increase the power by 1, then divide by the new power.

Given <u>indefinite integral</u>:

\displaystyle \int x \ln x \:\: \text{d}x

To integrate the given integral, use Integration by Parts:

\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}

\text{Let }u=\ln x \implies \dfrac{\text{d}u}{\text{d}x}=\dfrac{1}{x}

\text{Let }\dfrac{\text{d}v}{\text{d}x}=x \implies v=\dfrac{1}{2}x^2

Therefore:

\begin{aligned}\displaystyle \int u \dfrac{dv}{dx}\:dx & =uv-\int v\: \dfrac{du}{dx}\:dx\\\\\implies \displaystyle \int x \ln x\:\:\text{d}x & = \ln x \cdot \dfrac{1}{2}x^2-\int \dfrac{1}{2}x^2 \cdot \dfrac{1}{x}\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x -\int \dfrac{1}{2}x\:\:dx\\\\& = \dfrac{1}{2}x^2\ln x - \dfrac{1}{4}x^2+\text{C}\end{aligned}

Learn more about integration here:

brainly.com/question/27805589

brainly.com/question/27983581

brainly.com/question/27759474

5 0
2 years ago
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