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Stella [2.4K]
3 years ago
10

Bella has a cell phone plan in which she pays for each call minute and text message she sends. The total number of minutes used

and text messages sent last month was 561. If call minutes cost 8 cents each and text messages cost 5 cents each and her bill was $34.26. how many minutes did she use?
Mathematics
1 answer:
iVinArrow [24]3 years ago
5 0

Answer:

⇒Let the no. of call minute be = x

⇒& no. of text messages be = y

⇒As total number of minutes used and text messages sent last month was 561

So x + y = 561.................................(1)

⇒Now as call minutes cost 8 cents each and text messages cost 5 cents each and her bill was $34.26

So 8x + 5y = 3426............................(2)

On solving equation 1 & 2 we have

we got x = 354 cent

& y = 207 cent

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Answer:

The answer to the question is;

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Step-by-step explanation:

Let the sample size =n = 100

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A Binomial distribution is appropriate where there is a chance for a certain number of successful outcomes from a number of independent trails

However n·p and n·q must be ≥ 5 for there to be a normal approximation of a Binomial distribution thus

n·p = 105×0.05 =  5.25 ≥ 5

and n·q = n(1 - p) = 105 (1 - 0.05) = 99.75 ≥ 5

As the requirements are met, we can proceed with the approximation of the Binomial distribution by the normal distribution

 z = \frac{x-np}{\sqrt{np(1-p)}  } = \frac{4.5 - 105*0.05}{\sqrt{105*0.05(1-0.05)} } =  - 0.3358

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Another way to solve the question is as follows

p = 0.95 q = 0.05

μ = np = 0.95*105 = 99.75, σ = \sqrt{npq} = 2.233

P (x≤100) = P(z = P(z<0.34) = 0.63307.

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Answer:

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