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4 years ago

12

In space, the intersection of two planes is

1 answer:

Len [333]4 years ago

5 0

<span>If these planes are not parallel then intersection would </span>form a line.

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Need help with finding the surface area and volume for this please thanks I just need step by step help so I can understand it m

Allisa [31]

Answer:

144

Step-by-step explanation:

First, do the top and bottom. The top is 2*4*3 or 24, and the bottom is 6*4 or 24.

Now, do the sides. It is a staircase that you can split into 6 2x2 blocks, or 6*4=24. Do the same with the other side to get 24 again.

Now for the front and back. This is 2*4*3 and 6*4 again, or 24 and 24.

Now you have 6 24's so just multiply these and get 144.

6 0

3 years ago

David’s bowling score is 1 less than 3 times Aaron’s score. The sum of their scores is 179. Find the score of each student, Use

VladimirAG [237]

Answer: David = 160, Aaron = 55

Step-by-step explanation:

6 0

3 years ago

How much will it cost to run for 8 hours at a cost of $0.13 per<br> kilowatt-<br> hour?

Tanzania [10]

Answer: $1.04

8 times .13 = 1.04

8 0

3 years ago

If possible, complete the equation below that uses the law of cosines to find the remaining side of the triangle.

romanna [79]

Answer:

Option C.

a = 20.3

Step-by-step explanation:

Given:

m<A = 32°

a = ??

b = 16

c = 32

Required:

Find a

SOLUTION;

To find the missing side, a, of the triangle, apply the Law of Cosines, $a^2 = b^2 + c^2 - 2bcCosA$

Plug in the values into the equation:

$a^2 = 16^2 + 32^2 - 2(16)(32)Cos32$

$a^2 = 1,280 - 1,024*Cos32$

$a^2 = 1,280 - 868.40125$

$a^2 = 411.59875$

$a = \sqrt{411.59875}$

$a = 20.3$ (nearest tenth)

4 0

3 years ago

Two distinct number cubes, one red and one blue, are rolled together. Each number cube has sides numbered 1 through 6.

cestrela7 [59]

Answer:

$P(E_1 or E_2) = \frac{7}{12}$

Step-by-step explanation:

Given

Two cubes of side 1 - 6

Required

Probability that the outcome of the roll is an odd sum or a sum that is a multiple of 5

First, the sample space needs to be listed;

Let $C_r$ represent the Red cube

$C_b$ represent the Blue cube

S represent the sample space

$C_r = (1,2,3,4,5,6)\\C_b = (1,2,3,4,5,6)\\S = (2,3,4,5,6,7,3,4,5,6,7,8,4,5,6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12)$ S is gotten by getting the sum of $C_r$ and $C_b$

$n(S) = 36$

<em>Calculating the Probability</em>

Let $E_1$ represent the event that an outcome is an odd sum

$E_1 = (3,5,7,3,5,7,5,7,9,5,7,9,7,9,11,7,9,11)$

$n(E_1) = 18$

$P(E_1) = \frac{n(E_1)}{n(S)}$

$P(E_1) = \frac{18}{36}$

Let $E_2$ represent the event that an outcome is a multiple of 5

$E_2 = (5,5,5,5,10,10,10)$

$n(E_2) = 7$

$P(E_2) = \frac{n(E_2)}{n(S)}$

$P(E_2) = \frac{7}{36}$

Let $E_3$ represent the event that an outcome is an odd sum and a multiple of 5

$E_3 = E_1 and E_2$

$E_3 = (5,5,5,5)$

$n(E_3) = 4$

$P(E_3) = \frac{n(E_3)}{n(S)}$

$P(E_3) = \frac{4}{36}$

Calculating $P(E_1 or E_2)$

$P(E_1 or E_2) = P(E_1) + P(E_2) - P(E_1 and E_2)$

$P(E_1 or E_2) = P(E_1) + P(E_2) - P(E_3)$

$P(E_1 or E_2) = \frac{18}{36} + \frac{7}{36} - \frac{4}{36}$

$P(E_1 or E_2) = \frac{18 + 7 - 4}{36}$

$P(E_1 or E_2) = \frac{21}{36}$

$P(E_1 or E_2) = \frac{7}{12}$

Hence, the probability that the outcome of the roll is an odd sum or a sum that is a multiple of 5 is $\frac{7}{12}$

6 0

3 years ago