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Serjik [45]
2 years ago
10

Add. (−2+6x^3−3x^2)+(4x^3−5+x^2)

Mathematics
1 answer:
Gemiola [76]2 years ago
7 0

Answer:

10x^3 - 2x^2 -7

Step-by-step explanation:

To subtract polynomials, you want to subtract the biggest exponent from the first polynomial to the second

so 6x^3 + 4x^3 and that would be 10x^3

then -3x^2 + x^2 and the negative is larger so it would be -2x^2

and finally -2 + -5 and that is -7

hope this helps! :)

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Step 1: Subtract 6 to get to 0.

-6 - 6 = 0.

Step 2: Add 6.

0 + 6 = 6.

Answer = 6

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Using the given information, give the vertex form equation of each parabola.
Amanda [17]

Answer:

The equation of parabola is given by : (x-4) = \frac{-1}{3}(y+3)^{2}

Step-by-step explanation:

Given that vertex and focus of parabola are

Vertex: (4,-3)

Focus:(\frac{47}{12},-3)

The general equation of parabola is given by.

(x-h)^{2} = 4p(y-k), When x-componet of focus and Vertex is same  

(x-h) = 4p(y-k)^{2}, When y-componet of focus and Vertex is same

where Vertex: (h,k)

and p is distance between vertex and focus

The distance between two points is given by :

L=\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}

For value of p:

p=\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}

p=\sqrt{(4-\frac{47}{12})^{2}+((-3)-(-3))^{2}}

p=\sqrt{(\frac{1}{12})^{2}}

p=\frac{1}{12} and p=\frac{-1}{12}

Since, Focus is left side of the vertex,

p=\frac{-1}{12} is required value

Replacing value in general equation of parabola,

Vertex: (h,k)=(4,-3)

p=\frac{-1}{12}

(x-h) = 4p(y-k)^{2}

(x-4) = 4(\frac{-1}{12})(y+3)^{2}

(x-4) = \frac{-1}{3}(y+3)^{2}

8 0
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