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2 years ago

Joey rode his bicycle 125 yds. The diameter tire is 25 inches. How many whole revolutions did the tire make (1 yd= 36 inches) ?

Mathematics

1 answer:

laila [671]2 years ago

3 0

Answer:

Step-by-step explanation:

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What is #5 I don’t know the answer.

denpristay [2]

If the axis of symmetry is x=-1, the vertex will have x-coordinate -1.

The point (0, 5) cannot be the vertex. The friend is not correct.

_____

If the point (1, 5) is on the graph so is the image of that point when it is reflected across the axis of symmetry. That image point is (-3, 5). A parabola that goes through points (1, 5) and (-3, 5) will not go through point (0, 5).

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2 years ago

Tommy has 6 more than 3 times the amount of money in his bank account than Judy. Judy has $7500 more than a number in her accoun

Ad libitum [116K]

Answer:

Amount of money Judy has in her account is $\$(7500+n)$ .

Amount of money Tommy has in his account is $\$(22506+3n)$

Step-by-step explanation:

To find : Amount of money in Judy account and amount of money in Tommy account:

Solution:

Given:

Judy has $7500 more than a number in her account.

Let the number be 'n'.

So we can say that;

Amount of money in Judy account is equal to 7500 plus number.

framing in equation form we get;

Amount of money in Judy account = $\$(7500+n)$

Hence Amount of money Judy has in her account is $\$(7500+n)$ .

Now Given:

Tommy has 6 more than 3 times the amount of money in his bank account than Judy.

So we can say that;

Amount of money in Tommy account is equal to 3 multiplied by Amount of money in Judy account plus 6.

framing in equation form we get;

Amount of money in Tommy account = $3(7500+n)+6 =22500+3n+6=\$(22506+3n)$

Hence Amount of money Tommy has in his account is $\$(22506+3n)$ .

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2 years ago

Dave rented a limousine for his wife's birthday. The hourly rate is $70. They used the limousine for 4 hours, plus Dave gave the

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Add all of them up then divide by 10

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2 years ago

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May someone pls help with this?

NemiM [27]

Answer:

p = 308

Step-by-step explanation:

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2 years ago

A ball with mass m kg is thrown upward with initial velocity 28 m/s from the roof of a building 17 m high. Neglect air resistanc

Nutka1998 [239]

a. At its maximum height, the ball has zero vertical velocity, so

$-\left(28\dfrac{\rm m}{\rm s}\right)^2=2(-g)(y_{\rm max}-17\,\mathrm m)$

$\implies y_{\rm max}=57\,\mathrm m$

b. The ball's height in the air $y$ at time $t$ is given according to

$y=17\,\mathrm m+\left(28\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2$

Solve for $t$ when $y=0$ :

$17+28t-4.9t^2=0\implies t\approx6.3\,\mathrm s$

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2 years ago