<span>
since y = –1.5x² its domain is R=] -infinity, infinity[
the inverse of y
</span>–1/1.5 y = x² , and x = sqrt ((–1/1.5) y) , and f^-1 (x) = sqrt ((–1/1.5) x)
its domain is –1/1.5) x>=0, so x<=0,
from where, the range of y = –1.5x² is the interval ]-infinity, 0]
6 2/3 ÷ 1/5 = 62/15
62/15=60 2/15
60 2/15 is your answer.
Hoped I helped!
<h3>
Answer: B. 26</h3>
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Use law of cosines to find angle A
a^2 = b^2 + c^2 - 2*b*c*cos(A)
9^2 = 6^2 + 14^2 - 2*6*14*cos(A)
81 = 36 + 196 - 168*cos(A)
81 = 232 - 168*cos(A)
81 - 232 = -168*cos(A)
-151 = -168*cos(A)
-168*cos(A) = -151
cos(A) = (-151)/(-168)
cos(A) = 0.8988095
A = arccos(0.8988095)
A = 25.9979801
A = 26 degrees approximately
Answer:
y-1=
(x+8)
Step-by-step explanation:
1. y-y1=m(x-x1) (point slope form)
2. y1 is the y of your given point and x1 is the x of your given point
3. m is the slope
