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Maurinko [17]
3 years ago
14

If f(x)f(x) is an exponential function where f(4.5)=23f(4.5)=23 and f(8)=42f(8)=42, then find the value of f(5.5)f(5.5), to the

nearest hundredth.
Mathematics
1 answer:
nydimaria [60]3 years ago
5 0

Answer:

f(5.5)≈27.32

Step-by-step explanation:

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N = 45

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The least common multiple of 2, 5, 6, and 9 is<br><br> A. 60.<br> B. 45.<br> C. 90.<br> D. 180.
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The least common multiple between those following numbers is C. 90.
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3 years ago
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Use substitution to solve the system of equations.
gtnhenbr [62]
(3.75, 5.5)

(Work is attached )
When using substitution , you substitute with a variable that is already by itself. In this case, the variable “y” is already by itself and equal to x+ 1.75 . you substitute that for the the y in the other equation and solve for the other variable which is “x”. After you solve for x , to find your y value, you have to substitute the x value in for either equation.

3 0
2 years ago
A sock drawer contains eight navy blue socks and five black socks with no other socks. If you reach in the drawer and take two s
Rzqust [24]

Answer:

a. the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b. the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c. the probability of either 2 navy socks is picked or one black  & one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

Step-by-step explanation:

A sock drawer contains 8 navy blue socks and 5 black socks with no other socks.

If you reach in the drawer and take two socks without looking and without replacement, what is the probability that:  

Solution:

total socks = N = 8 + 5 + 0 = 13

a) you will pick a navy sock and a black sock?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick the black sock, total number of socks left is 12.

Let B be the probability of picking a black sock again.

 P (B) = 5/12.

Then, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b) the colors of the two socks will match?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick another navy sock, total number of socks left is 12.

Let B be the probability of another navy sock again.

 P (B) = 7/12.

Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

Let D be the probability of picking a black socks first.

Then P (D) = 5/13

without replacing the black sock, will pick another black sock, total number of socks left is 12.

Let E be the probability of another black sock again.

 P (E) = 4/12.

Then, the probability of picking 2 black sock = P (D & E)

= (5/13 ) * (4/12) = 5/39 = 0.128

Now, the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c) at least one navy sock will be selected?

this means, is either you pick one navy sock and one black or two navy socks.

so, if you will pick a navy sock and a black sock, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

also, if you will pick 2 navy sock, Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

now either 2 navy socks is picked or one black  one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

4 0
2 years ago
X = 8 9 10<br> Plzzz helpppo
Novosadov [1.4K]
The answer should be 9
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3 years ago
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