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2 years ago

(I do brainliest.) slope intercept form... [show ya work plz]

Mathematics

1 answer:

eduard2 years ago

3 0

Answer:

y = 3x+2

Step-by-step explanation:

(3,7) (6,9) Y2=9 Y1=7 X2=6 X1=3

M = 9-7/6/3

2/3

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Wall c is 4 m to represent wall c Noah draws a segment 16 cm Long what scale is he using

RSB [31]

Answer:

Scale using for plan ⇒ 1 m = 4 cm

Step-by-step explanation:

3 0

3 years ago

Find the absolute maximum and absolute minimum values of the function f(x, y) = x 2 + y 2 − x 2 y + 7 on the set d = {(x, y) : |

dsp73

Looks like $f(x,y)=x^2+y^2-x^2y+7$ .

$f_x=2x-2xy=0\implies2x(1-y)=0\implies x=0\text{ or }y=1$

$f_y=2y-x^2=0\implies2y=x^2$

If $x=0$ , then $y=0$ - critical point at (0, 0).
If $y=1$ , then $x=\pm\sqrt2$ - two critical points at $(-\sqrt2,1)$ and $(\sqrt2,1)$

The latter two critical points occur outside of $D$ since $|\pm\sqrt2|>1$ so we ignore those points.

The Hessian matrix for this function is

$H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}2-2y&-2x\\-2x&2\end{bmatrix}$

The value of its determinant at (0, 0) is $\det H(0,0)=4>0$ , which means a minimum occurs at the point, and we have $f(0,0)=7$ .

Now consider each boundary:

If $x=1$ , then

$f(1,y)=8-y+y^2=\left(y-\dfrac12\right)^2+\dfrac{31}4$

which has 3 extreme values over the interval $-1\le y\le1$ of 31/4 = 7.75 at the point (1, 1/2); 8 at (1, 1); and 10 at (1, -1).

If $x=-1$ , then

$f(-1,y)=8-y+y^2$

and we get the same extrema as in the previous case: 8 at (-1, 1), and 10 at (-1, -1).

If $y=1$ , then

$f(x,1)=8$

which doesn't tell us about anything we don't already know (namely that 8 is an extreme value).

If $y=-1$ , then

$f(x,-1)=2x^2+8$

which has 3 extreme values, but the previous cases already include them.

Hence $f(x,y)$ has absolute maxima of 10 at the points (1, -1) and (-1, -1) and an absolute minimum of 0 at (0, 0).

3 0

3 years ago

Let u= <4,3>. Find the unit vector in the direction of u, and write your answer in component form.

aksik [14]

Take the vector u = <ux, uy> = <4, 3>.

Find the magnitude of u:

||u|| = sqrt[ (ux)^2 + (uy)^2]

||u|| = sqrt[ 4^2 + 3^2 ]

||u|| = sqrt[ 16 + 9 ]

||u|| = sqrt[ 25 ]

||u|| = 5

To find the unit vector in the direction of u, and also with the same sign, just divide each coordinate of u by ||u||. So the vector you are looking for is

u/||u||

u * (1/||u||)

= <4, 3> * (1/5)

= <4/5, 3/5>

and there it is.

Writing it in component form:

= (4/5) * i + (3/5) * j

I hope this helps. =)

3 0

3 years ago

Max has just won some money on a game show! He has the option to take a lump sum payment of $500,000 now or get paid an annuity

Fofino [41]

Answer:

The second option annually

Step-by-step explanation:

(4,900×12)×10 the multiply by 2.9%. Take that number and add on every 10 years

3 0

3 years ago

one apartment costs $1000 a month with deposit off $1500. Another apartment costs 1175 a month with a 1200 deposit. how many mon

kkurt [141]

3 or 4 because if you add 1000 and 1500,1175 and 1200.

8 0

3 years ago