Ken's distance is: d(t)=1.7t
Ken's shadow is:
(14-6)/d(t)=14/s
8/d(t)=14/s
s=14d(t)/8
s=1.75d(t) and using the value for d(t) we have:
s=1.75(1.7t)
s=2.975t and if you want it in terms of d, d=1.7t, t=d/1.7 so
s=2.975(d/1.7)
s=1.75d
First you divide 39/40
you would get 0.975
<h3>
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➷ Find the scale factor:
15/6 = 2.5
Multiply this by the length
2 x 2.5 = 5
x = 5 in
<h3><u>
✽</u></h3>
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Answer:
x = 5
Step-by-step explanation:
Solve for x:
2 (2 x - 5) = 3 x + x - 2 x
3 x + x - 2 x = 2 x:
2 (2 x - 5) = 2 x
Divide both sides by 2:
2 x - 5 = x
Subtract x from both sides:
(2 x - x) - 5 = x - x
2 x - x = x:
x - 5 = x - x
x - x = 0:
x - 5 = 0
Add 5 to both sides:
x + (5 - 5) = 5
5 - 5 = 0:
Answer: x = 5
Answer:
6
Step-by-step explanation:
the answer would be 5.70588235294, but if you are rounding to the nearest tenth, its 6