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kenny6666 [7]
2 years ago
14

What is the solution to the given inequality?

Mathematics
1 answer:
xenn [34]2 years ago
7 0

Answer: x ≤3

Step-by-step explanation:

Your answer is correct

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The graph shows two lines, A and B.
zheka24 [161]

Answer:

statement 1 is the only correct one

Step-by-step explanation:

8 0
3 years ago
Eqyivalent expresion to 3√m^2n^5
Irina18 [472]
The first step to solving this expression is to factor out the perfect cube
\sqrt[3]{m^{2}  n^{3} X n^{2}   }
The root of a product is equal to the product of the roots of each factor. This will make the expression look like the following:
\sqrt[3]{ n^{3} } \sqrt[3]{ m^{2} n^{2}  }
Finally,, reduce the index of the radical and exponent with 3
n\sqrt[3]{ m^{2} n^{2}  }
This means that the correct answer to your question is n\sqrt[3]{ m^{2} n^{2} } .
Let me know if you have any further questions
:)
8 0
3 years ago
Find the value of 5 ∙ 23. <br><br> 30<br><br> 40 <br><br> 1,000<br><br> ASAP
True [87]

The value of 5 ∙ 23 is 115.

The small dot is typically used as a multiplication symbol. When we multiply these two numbers the result is 115.

5 0
3 years ago
Read 2 more answers
Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997, However in march 1997 the price of the tea increased by 25% and
Irina18 [472]

Answer: tea = 15 rupees  per kg

sugar= 3 rupees per kg

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations with the information given:

<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997": </em>

2 t + 3 s =39 (a)

Where:

  • t= price of 1 kg of tea
  • s = price of 1 kg of sugar

<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30. "</em>

2(t1.25)+3(s1.2) = 48.30 (b)

  • <em>Solving for t in (b) </em>

2t =39-3s

t = (39 -3s)/2

t = 19.5-1.5s

  • <em>Replacing the value of t in (b) </em>

2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30

2x ( 24.375 -1.875s) +3.6s =48.30

48.75 -3.75s+3.6s= 48.30

48.75-48.30 = 3.75s-3.6s

0.45= 0.15s

0.45/0.15 =s

3 =s

  • <em>Replacing the value of s in (a) </em>

2 t + 3 (3) =39

2 t + 9 =39

2 t =39 -9

2 t =30

t = 30/2

t= 15

Prices in january:

tea = 15 rupees per kg

sugar= 3 rupees per kg

Feel free to ask for more if needed or if you did not understand something.

4 0
3 years ago
Read 2 more answers
Find the measures of the numbered angles.
Arte-miy333 [17]
1 = 90
2 = 65
3 = 65
4 = 25

90+25=115
180-115=65

have a merry christmas :)
3 0
2 years ago
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