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3 years ago

Please help I’ve been stuck for 2 hours

Chemistry

1 answer:

Vinvika [58]3 years ago

7 0

find the answer in the attached image. please mark as brainliest if it is helpful.

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Determine the mass in grams of Avogadro's number of C12H22O11

Allushta [10]

Answer:

2.059524x10^26 if im not wrong

Explanation:

avogadro's number is 6.022x10^23

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3 years ago

Fill in the coefficients that will balance the following reaction: a0Na + a1H2O → a2NaOH + a3H2

Alexandra [31]

Hey there ! :

2 Na + 2 H2O = 2 NaOH + 1 H2

Sodium + Dihydrogen Monoxide = Natriumhydroxid + Hydrogen

Coefficients:

Reagents : Na = 2
H2O = 2

Products : NaOH = 2
H2 = 1

4 0

4 years ago

Read 2 more answers

15 grams of sodium reacts with a certain amount of chlorine to yield 37 grams of sodium chloride, as shown below.

ale4655 [162]

Answer: 22g of chlorine would be needed to carry out this synthesis reaction

Explanation:

A synthesis reaction is one in which two or more than two elements combine together to forma single product.

$Na+Cl\rightarrow NaCl$

The atoms present in the reactants are found on the product side. According to the law of conservation of mass, the number of atoms on both sides of the arrow must be same as the total mass must be conserved.

15 grams of sodium reacts with 22 grams of chlorine to yield 37 grams of sodium chloride. Thus 22g of chlorine would be needed to carry out this synthesis reaction.

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3 years ago

TRUE or FALSE: The rock closest to the ridge is newer and younger than the older rock

alina1380 [7]

Answer:true

Explanation:

7 0

3 years ago

How many milliliters of a 0.285 M HCl solution are needed to neutralize 249 mL of a 0.0443 M Ba(OH)2 solution?

meriva

Answer:

$\large \boxed{\text{77.4 mL}}$

Explanation:

Ba(OH)₂ + 2HCl ⟶ BaCl₂ + H₂O

V/mL: 249

c/mol·L⁻¹: 0.0443 0.285

1. Calculate the moles of Ba(OH)₂

$\text{Moles of Ba(OH)$_{2}$} = \text{0.249 L Ba(OH)}_{2} \times \dfrac{\text{0.0443 mol Ba(OH)}_{2}}{\text{1 L Ba(OH)$_{2}$}} = \text{0.011 03 mol Ba(OH)}_{2}$

2. Calculate the moles of HCl

The molar ratio is 2 mol HCl:1 mol Ba(OH)₂

$\text{Moles of HCl} = \text{0.011 03 mol Ba(OH)}_{2} \times \dfrac{\text{2 mol HCl}}{\text{1 mol Ba(OH)}_{2}} = \text{0.022 06 mol HCl}$

3. Calculate the volume of HCl

$V_{\text{HCl}} = \text{0.022 06 mol HCl} \times \dfrac{\text{1 L HCl}}{\text{0.285 mol HCl}} = \text{0.0774 L HCl} = \textbf{77.4 mL HCl}\\\\\text{You must add $\large \boxed{\textbf{77.4 mL}}$ of HCl.}$

8 0

4 years ago