AFC = FC / Quantity printed
<span>So given she prints 1,000 posters: AFC = 250.00/1000 = $0.25 </span>
<span>Given she prints 2,000 posters: AFC = 250.00/2000 = $0.125 </span>
<span>Given she prints 10,000 posters: AFC = 250.00/2000 = $0.025 </span>
<span>ATC = TC / Quantity printed </span>
<span>where TC = FC + Variable C * Quantity printed </span>
<span>If she prints 1000: TC = 250 + 2000*1000 = 2,000,250 </span>
<span>ATC = 2,000,250/1000 = 2000.25 </span>
<span>If she prints 2000: TC = 250 + 1600*2000 = 3,200,250 </span>
<span>ATC = 3,200,250/2000 = 1600.125 </span>
<span>If she prints 10000: TC = 250 + 1600*2000 + 1000*8000 ($1000 for each additional poster after 2000) = 11,200,250 </span>
<span>ATC = 11,200,250/10000 = 1120.025</span>
Answer:
8 - 2π square units.
π/16 - 1/8 square units.
6π - 9√3 square units.
Step-by-step explanation:
The area of the square = 2√2 * 2√2
= 2*2*2
= 8.
The area of the circle = πr^2
= π * [ ( 2√2)/ 2) ]^2
= π (√2)^2
= 2π.
Second Question:
The area of the circle = π(1/2)^2 = π/4.
Finding the area of the square:
1^2 = 2x^2
x^2 = 1/2
So the area of the square = 1/2
So the area of the red part = 1/4 ( π/4 - 1/2).
= π/16 - 1/8.
Third question
Area of the circle = 6^2 * π = 36π.
Now 60 degrees is 1/6 of 360 degrees so the are of the sector is 6π.
The area of the segment = 6π - 0.5 * 6^2 sin 60
= 6π - 18√3/2
= 6π - 9√3 square units.
It would be (12,20) or (20,12) I don't know which one
There are a few ways to solve this. The method I will use is the substitution method. Since they give us a "y = " statement, we can replace the y in the second equation with what it gives us to the right of the equal sign.
- 3x + 6(- 2x - 1) = 24
Simplify by using the distributive property.
- 3x + 6(- 2x) + 6(- 1) = 24
- 3x - 12x - 6 = 24.
Combine like terms
- 15x - 6 = 24
Add 6 to each side.
- 15x = 30
Divide both sides by - 15 to isolate variable X
x = 30 / - 15
x = - 2.
Now plug in the x-value we've found back into the first equation.
y = - 2( - 2) - 1
y = 4 - 1
y = 3
Your answer is (- 2, 3)
