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antoniya [11.8K]
2 years ago
9

A study is run comparing HDL cholesterol levels between men who exercise regularly and those who do not. The data are shown belo

w.
Generate a 95% confidence interval for the difference in mean HDL levels between men who exercise regularly and those who do not.
Mathematics
1 answer:
kow [346]2 years ago
3 0

Answer:

Hello your question is incomplete attached below is the missing part of the question

Regular Exercise           N                             Mean                          Std Dev

Yes                                35                             48.5                                12.5

No                                  120                           56.9                                11.9

answer : ( -12.968, -3.832 )

Step-by-step explanation:

To generate a 95% confidence interval

<u>first step :</u>

Assume population variance is equal we will calculate the number of degrees of freedom

df = n1 + n2 - 2 = 35 + 120 -2 = 153

<u>second step:</u>

Given : critical value = 0.05 , df = 153

hence Tc = 1.976

assuming the population variance is equal calculate pooled std as ( attached below )

Sp = 12.036

<u>third step :</u>

calculate the standard error

Se = Sp\sqrt{\frac{1}{n1} +\frac{1}{n2} }

n1 = 35

n2 = 120

Sp = 12.036

hence Se = 2.312

<u>final step </u>

Compute the 95% confidence interval = ( -12.968, -3.832 )

attached below is the detailed solution

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in the given figure ,o is the centr of the circle, ab is the diameter and do is perpendicular to ab. prove that angle AEC= ANGLE
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The given triangles ΔDOA and ΔABC are right triangles that have a

common vertex at point <em>A</em>.

  • <u>ΔDOA is similar to ΔABC, and </u><u>∠AEC</u><u> is equal to </u><u>∠ABC,</u><u> therefore, ∠AEC = ∠ODA</u>

Reasons:

The given parameters are;

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Required:

Prove that ∠AEC = ∠ODA

A two column proof is presented as follows;

Statement {}                                                 Reason

1. AB is the diameter of circle     <em> </em>{}                 1. Given

2. DO is perpendicular to AB <em> </em>{}                     2. Given

3. ∠DOA = 90° <em> </em>{}                                             3. Definition of DO ⊥ AB

4. ∠BCA = 90°  <em> </em>{}                                             4. Thales theorem

5. ∠BCA ≅ ∠BCA <em> </em>{}                                         5. Reflexive property

6. ΔDOA ~ ΔABC  <em> </em>{}                                        6. AA similarity postulate

7. ∠ABC ≅ ∠ODA  <em> </em>{}                                       7. CASTC

8. ∠ABC = ∠ODA  <em> </em>{}                                        8. Definition of congruency

9. ∠AEC ≅ ∠ABC  <em> </em>{}                                        9. Angles in the same segment

10. ∠AEC = ∠ABC  <em> </em>{}                                       10. Definition of congruency

11. ∠AEC = ∠ODA  <em> </em>{}                                        11. Transitive property of equality

In statement 6, ΔDOA is similar to ΔABC by Angle-Angle, AA, similarity

postulate, therefore, the three angles of ΔDOA are congruent to the three

angles of ΔABC.

Therefore ∠ABC ≅ ∠ODA by Corresponding Angles of Similar Triangles

are Congruent, CASTC.

Learn more about circle theorem here:

brainly.com/question/16879446

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