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Marina CMI [18]
3 years ago
11

The angle θ lies in Quadrant II .

Mathematics
1 answer:
Andreyy893 years ago
6 0

let's keep in mind that, in the II Quadrant, cosine is negative and sine, is positive.

cosine is adjacent/hypotenuse, however the hypotenuse is simply a radius unit, and thus is never negative, so in the -(2/3) the negative must be the numerator, -2.


\bf cos(\theta )=\cfrac{\stackrel{adjacent}{-2}}{\stackrel{hypotenuse}{3}}\impliedby \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{3^2-(-2)^2}=b\implies \pm\sqrt{5}=b\implies \stackrel{\textit{II Quadrant}}{+\sqrt{5}=b}~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\sqrt{5}}}{\stackrel{adjacent}{-2}} \\\\\\ ~\hspace{34em}

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Answer:

Option (2) is correct.

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Step-by-step explanation:

Given expression 18-\sqrt{-25}

We have to find an equivalence value to the expression.

<u> Radical rule</u>,

\sqrt{-a}=\sqrt{-1} \sqrt{a}

Also,i=\sqrt{-1}

Consider the given expression,

18-\sqrt{-25}

Applying radical rule to \sqrt{-25}

\sqrt{-25}=\sqrt{-1}\sqrt{25}=5i

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Which characteristic is correct for the function f(x)=−2x^3+3x ?
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Step-by-step explanation:

Let us under stand the basics of determining the end behavior of a graph , by just analyzing the degrees and coefficient of a polynomial.Please refer to the image we have shared with this for a better understanding also.

The rule is bifurcated in two broad category and and two sub category in them.

Category .

The nature of degree (Even / Odd )

Subcategory .

The coefficient of term containing degree ( Negative/Positive )

Rule 1 :

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If coefficient is

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Rule 2 :

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Here

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