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Vadim26 [7]
3 years ago
8

I’ll give brainiest if rightttt !!! :)

Mathematics
2 answers:
sergiy2304 [10]3 years ago
6 0

Answer:

its 123 and 4,

Step-by-step explanation:

did i get it right, bc one of those is

katrin2010 [14]3 years ago
5 0
5/2 is the correct answer
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Fifty multiplied by the quantity twenty divided by a number n is greater than or equal to two hundred fifty
Fudgin [204]
4 is the correct answer
8 0
3 years ago
Two number cubes are rolled. What is the probability that the sum of the numbers rolled is either 4 or 8?
sveticcg [70]

There are 6 numbers on each die.

The total number of out comes is 6 x 6 = 36.


To get a sum of 4, the combinations are: 1 & 3, 2 & 2 or 3 & 1.

To get a sum of 8, the combinations are: 1 & 7, 2 & 6, 3 & 5, 4 & 4, 7 & 1, 6 & 2, 5 & 3


The total of those combinations are:  3  + 7 = 10 total combinations of a sum of either 4 or 8.


The probability of either is 10/36, which can be reduced to 5/18.

8 0
3 years ago
The graph above is a transformation of the function x2 Write an equation for the function graphed above
lutik1710 [3]

Answer: y=0,5x²-x-1,5.

Step-by-step explanation:

(-1;0)\ \ \ \ (3;0)\ \ \ \ (1;-2)   \ \ \ \  y=ax^2+bx+c\ ?\\\left\{\begin{array}{ccc}a*(-1)^2+b*(-1)+c=0\\a*3^2+b*3+c=0\\a*1^2+b*1+c=-2\end{array}\right \ \ \ \  \ \left\{\begin{array}{ccc}a-b+c=0\ \ (1)\\9a+3b+c=0\ (2)\\a+b+c=-2\ (3)\end{array}\right  \\

We summarize (1) and (3):

2a+2c=-2\ |:2\\a+c=-1\ \ \ \ \Rightarrow\\a+b+c=-2\\(a+s)+b=-2\\-1+b=-2\\b=-1.

Substitute b=-1 into (2):

9a+3*(-1)+c=0\\9a-3+c=0\\9a+c=3\ \ (5).\\

From (5) subtract (4):

8a=4\ |:8\\a=0,5.\ \ \ \  \Rightarrow\\

Substitute a=0,5 into (4):

0,5+c=-1\\c=-1,5.

Hense:

y=0,5x²-x-1,5.

5 0
2 years ago
Would the mean or median best describe the following data?
abruzzese [7]
36 is the median and add them all then divide by 5 to get the mean 

8 0
4 years ago
Read 2 more answers
Scott tossed a wad of paper. It landed in
iris [78.8K]

Answer:

36 times.

Step-by-step explanation:

3/5=0.6

2/5=0.4

60*0.6=36

7 0
2 years ago
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