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Vadim26 [7]
4 years ago
8

I’ll give brainiest if rightttt !!! :)

Mathematics
2 answers:
sergiy2304 [10]4 years ago
6 0

Answer:

its 123 and 4,

Step-by-step explanation:

did i get it right, bc one of those is

katrin2010 [14]4 years ago
5 0
5/2 is the correct answer
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From a plane flying due east at 265 m above sea level, the angles of depression of two ships sailing due east measure 35 degrees
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Answer:

189.8 m

Step-by-step explanation:

See the diagram attached.

Now, the plane is at B and the two ships are at C and at D.

So, angle of depression of C from B is ∠ OBC = ∠ ACB = 35°

Again, the angle of depression of D from B is ∠ OBD = ∠ ADB = 25° ,

Now, from the right triangle Δ ACB,  

\tan 35 = \frac{AB}{AC} = \frac{265}{AC}

⇒ AC = \frac{265}{\tan 35} = 378.5 m.

Similarly, from the right triangle Δ ADB,

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⇒ AD = \frac{265}{\tan 25} = 568.3 m.

Hence, the distance between the ships = CD = AD - AC = 568.3 - 378.5 = 189.8 m (Approx.) (Answer)

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