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2 years ago

Halp plz first to get right gets brainlyist (don't mind my spelling)

Mathematics

1 answer:

inysia [295]2 years ago

8 0

Teresa is not correct because when the first expression is simplified, it is 3 less than the second expression.

Well, let’s simplify the first expression. Distribute the 2 to the (5x - 3) to get the expression to 10x - 6 + 6x. Now, combine like terms to get 16x - 6, which is not the same as 16x - 3.

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A right rectangular prism has edges of 8 feet, 4 feet, and 1/2 foot. How many cubes with side lengths of 1/2 foot would be neede

Ksenya-84 [330]

Answer:

Step-by-step explanation:

From the question we are told that

Edges of 8 feet, 4 feet, and 1/2 foot

Generally the volume V_p of the right rectangular prism is mathematically represented as

$V_p=8*4*0.5$

$V_p=16$

Generally volume of the cube V_c is mathematically given as

$V_c =(\frac{1}{2})^3$

$V_c =\frac{1}{6}$

Therefore total number of cubes is given as

$V=\frac{V_p}{V_c}$

$V=\frac{16}{\frac{1}{6}}$

$V=96$

4 0

3 years ago

What value should replace the "?" to make the equations parallel?

Otrada [13]

The same slope would make the equations parallel. Therefore 5/3 would make them parallel.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bx%7D%20%20-%20%20%20%7B3%7D%5E%7Bx%7D%20%20%3D%20%20%20%20%5Csqrt%7B%20%7B6%7D

strojnjashka [21]

Answer:

x = 0

Step-by-step explanation:

${2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {9}^{x } } \\ \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {( {3}^{2}) }^{x } } \\ \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {({3)}^{2x}}}\\ \\ {2}^{x} - \cancel{{3}^{x}} = \sqrt{ {6}^{x} } - \cancel{ {3}^{x} } \\ \\ {2}^{x} = \sqrt{ {6}^{x} } \\ squaring \: both \: sides \\ \\ {( {2}^{x} )}^{2} = {(\sqrt{ {6}^{x} })}^{2} \\ \\ {2}^{2x} = {6}^{x} \\ \\ {2}^{2x} = {(2 \times 3)}^{x} \\ \\ {2}^{2x} = {2 ^{x} \times 3}^{x} \\ \\ \frac{ {2}^{2x} }{ {2}^{x} } = 3^{x} \\ \\ {2}^{2x - x} = {3}^{x} \\ \\ {2}^{x} = {3}^{x} \\ \\ \frac{ {2}^{x} }{ {3}^{x} } = 1 \\ \\ \bigg( \frac{2}{3} \bigg)^{x} = 1 \\ \\ \implies \: x = 0 \\ \\ \because \: for \: x = 0 \\ \\ \bigg( \frac{2}{3} \bigg)^{0} = 1$

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