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Maksim231197 [3]
3 years ago
13

Halp plz first to get right gets brainlyist (don't mind my spelling)

Mathematics
1 answer:
inysia [295]3 years ago
8 0
Teresa is not correct because when the first expression is simplified, it is 3 less than the second expression.

Well, let’s simplify the first expression. Distribute the 2 to the (5x - 3) to get the expression to 10x - 6 + 6x. Now, combine like terms to get 16x - 6, which is not the same as 16x - 3.
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Can someone please help me:)
cluponka [151]
Choice 2222222222222222222222222222222
4 0
3 years ago
Part B
EastWind [94]

Answer:

Step-by-step explanation:

the slope of line n is also -3 as it is parallel to m

The answer is A

6 0
3 years ago
he given table shows the growth of Anytown, NC by providing the estimated population from 1970 to 2000. Year Population 1970 4,8
Morgarella [4.7K]
The population is increasing by 1500 each year  and starts at 1970 population ( = 4800)  so the equation is
y=1500x+4800
4 0
4 years ago
The ancient Greeks could bisect an angle using only a compass and straightedge.A. TrueB. False
Gala2k [10]

Answer: True.

The ancient Greeks could bisect an angle using only a compass and straightedge.

Step-by-step explanation:

The ancient Greek mathematician <em>Euclid</em> who is known as inventor of geometry.

The Greeks could not do arithmetic. They had only whole numbers. They do not have zero and negative numbers.

Thus, Euclid and the another Greeks had the problem of finding the position of an angle bisector.

This lead to the constructions using compass and straightedge. Therefore, the straightedge has no markings. It is definitely not a graduated-rule.

As a substitute for using arithmetic, Euclid and the Greeks learnt to solve the problems graphically by drawing shapes .

5 0
4 years ago
Read 2 more answers
The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t
wolverine [178]

Answer:

a) The implied differential equation is \frac{dN}{725 - N} = kdt

b) The general equation is N = 725 - C e^{-kt}

c) The particular equation is N = 725 - 325 e^{-0.49t}

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, \frac{dN}{dt} \alpha (725 - N(t))

\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt

Integrating both sides of the equation

\int {\frac{1 }{725 - N}} \, dN  = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}

When t = 0, N = 400

400 = 725 - C e^{-k*0}\\400 = 725 - C\\C = 725 - 400\\C = 325

When t = 3,  N = 650

650 = 725 - (325 * e^{-3k})\\325 * e^{-3k} = 75\\e^{-3k} = 75/325\\e^{-3k} = 0.23\\-3k = ln 0.23\\-3k = -1.47\\k = 1.47/3\\k = 0.49

The equation for the population becomes:

N = 725 - 325 e^{-0.49t}

At t = 5, the population becomes:

N = 725 - 325 e^{-0.49*5}\\N = 725 - 325 e^{-2.45}\\N = 696.95\\N(5) = 697

N(5) = 700 ( to the nearest 50)

6 0
3 years ago
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